Answer:
23) x= 3, y = 4
24) Any (x,y) values where x = 1.5 - 2y
Step-by-step explanation:
For the first system(23), it goes like this
[1 2 | 7]
[2 1 | 8]
We need to do L2 = L2 - 2L1, so now it is
[1 2 | 7]
[0 -3 |-6]
So, now we have:
-3y = -6 *(-1)
3y = 6
y = 2
x + 2y = 7
x + 4 = 7
x = 3
Now for system 24, we have:
[-1 2 | 1.5]
[2 -4| 3]
We do L2 = L2 + 2L1, so we have:
[-1 2 | 1.5]
[0 0| 0]
So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.
One is A
two is 7
three is t = 5W
Hello from MrBillDoesMath!
Answer:
-15
Discussion:
We are asked to evaulate:
abs(3) + ( -2 (3)^2) = => as abs(3) = 3
3 + (-2*9) =
3 - 18 =
-15
Thank you,
MrB
