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The answer is a <u>sequence structure</u>
We can define a word as a group of characters without a space between them. To find the words of the input string , w can use split(delimiter) which returns a list of strings which had the defined delimiter between them in the input string.
def countWords(string):
words = string.split(" ")
count = len(words)
return count
Here we set the delimiter as the space character, and returned the length of the words list. I split each step into its own line for readability, however the function could be one line:
return len(string.split())
Here, no delimiter is specified. If one isn't given, it will default to split at any whitespace, including space.