1. D linear
2. A quadratic
3. B exponential
4. C rational
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
infinite number of solutions
Step-by-step explanation:
Work with the second equation. Subtract 8x from both sides.
- 4y + 8x - 8x = -8x - 12 Collect like terms.
-4y = - 8x - 12 Divide by - 4
-4y/-4 = - 8x/-4 - 12/-4
y = 2x + 3
That is exactly the same line as the first given. There is an infinite number of solutions.
Switch the x and y values and isolate y, then simplify.
x=6y+5
6y=x-5
y=1/6x-5/6
