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Sunny_sXe [5.5K]
3 years ago
14

Distance Which expression could help you find the distance between (10, 4) and (–6, 4)? |10| + |–4| |10| + |4| |–6| + |4| |10| +

|–6|
Mathematics
2 answers:
kenny6666 [7]3 years ago
6 0

\bf \boxed{(-6,4)}\stackrel{\textit{6 units}}{\rule[0.35em]{10em}{0.25pt}}0\stackrel{\textit{10 units}}{\rule[0.35em]{15em}{0.25pt}}\boxed{(10,4)}
\\\\[-0.35em]
~\dotfill\\\\
~\hfill |10|+|-6|~\hfill

forsale [732]3 years ago
3 0

Answer:

d

Step-by-step explanation:

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At Garcia’s bike rentals it cost $23 to rent a bike for 6 hours. how many hours of bike use does a customer get per dollar? Roun
Ket [755]

Given:

Rental costs $23 to rent a bike for 6 hours.

\begin{gathered} \text{Customer get a bike rental for a dollar=}\frac{6}{23} \\ \text{Customer get a bike rental for a dollar=}0.26\text{ hours} \end{gathered}

A customer gets 0.26 hours as a rent for a dollar.

6 0
1 year ago
X square - 3 x - 4 equals 0​
kozerog [31]

Answer:

x=4 x=-1

Step-by-step explanation:

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4) + 1(x-4)=0

x+1=0

x=-1

x-4=0

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4 0
3 years ago
Help me represent this easy equation: For every unit of X you must produce 3 of Y
Sergio [31]

Answer:

Okay the, 3 of Y by every unit of X. Simple.

Step-by-step explanation:

5 0
3 years ago
Select all statements that are true about the graph of ordered pair (5, −1) . The point is 5 units below the x-axis. The point i
seropon [69]
The -1 means that y = -1, so point is one unit below the x-axis.  In (5, -1), the x is positive, which could put the point in either the first quadrant or the fourth.  With the y being negative, however, it means that the point is in the fourth quadrant.  Those are your 2 true statements.
8 0
3 years ago
Read 2 more answers
Find two geometric means between 5 and 135
aniked [119]
Answer:

We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.

This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>

Explanation:

In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.

So we want to find a and b such that 5, a, b, 135 is a geometric sequence.

If the common ratio is r then:

<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>

Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>

Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>


6 0
3 years ago
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