Find a formula for the nth term of the sequence in terms of n. the sequence 1, 0, 1, 0, 1, ...

1 answer:

3 0

If the sequence is like this, you actually don’t have to formulate a formula. You just have to formulate a principle. You just have to remember that when n is an odd number, the value would always be 1. If the n is an even number, the value would always be 0.

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4×(34−12)+3×6<br><br> No links i am bad at math

Inga [223]

Answer:

4×(34-12)+3×6

4×22+3×6

88+18

=106

Step-by-step explanation:

Apply the BEDMAS rule

B=brackets

E=exponents

D=Division

M=multiplication

A=addition

S=subtraction

8 0

3 years ago

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What is 9m + 2 = 3m - 10

cupoosta [38]

9m+2=3m-10
subtract 3m from both sides to get:
6m+2=-10
subtract 2 from both sides to get:
6m=-12
finally, divide by 6 on both sides to get what m equals:
m=-2

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3 years ago

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How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$