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olganol [36]
3 years ago
8

If def geh solve for x

Mathematics
2 answers:
dsp733 years ago
5 0
The answer is x I guess
Lerok [7]3 years ago
3 0

Answer:

huh???

Step-by-step explanation:

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brianne is three times as old as camila. four years from now she will be just two times ad old as camila. how old are brianna an
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The answer to the question

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3 years ago
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A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation
dangina [55]

Answer:

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=98.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=103-1=102

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that t_{\alpha/2}=2.62

Now we have everything in order to replace into formula (1):

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

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3 years ago
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What is -r-10r combine like terms
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-r -10r

fractor out -r

-r(1 +10)

-r(11)

-11r

Answr: -11r

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List the values that make up the domain of this relation. (5,3)(2,-7)(1,-8)(8,3)
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Kate is making pizza. She puts 8 ounces of cheese on each pizza. If she has 4 24-ounce packages of cheese, how many pizzas can s
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