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3 years ago

I need this two questions

Mathematics

1 answer:

Setler79 [48]3 years ago

4 0

Just solve.

$(17-k)^3\\k=12 \\ \\ (17-12)^3 \\ \\ (5)^3 \\ \\ 125\\$

$\\\\(5+2n)^5 \\ n=-2 \\ \\ (5+2(-2))^5 \\ \\ (5-4)^5 \\ \\ (1)^5 \\ \\ 1$

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In a company, 85% of the workers are men. If 360 people work for the company who aren't men, how many workers are there in

geniusboy [140]

If 85% are men, then (100 - 85), 15% are not men

so, 15% are not men which means that 15% are 360 = 15% of x = 360

(x = total no. of workers)

so, x = 360 × $\frac{100}{15}$ = 2400

The total number of people = 2400

( sorry I didn't use pencil...)

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3 years ago

Azul bought 10 reams of paper at the store for a total of $84 the tax on the purchase was $4 what was the cost of each room of p

bogdanovich [222]

He paid 10 for each ream so
10r
Then there was a 4 dollar tax so
10r+4
the total was 84
10r+4=84

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3 years ago

The directex of Y=1/8x^2 is?

nexus9112 [7]

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})} \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
y=\cfrac{1}{8}x^2\implies (y-0)=\cfrac{1}{8}(x-0)^2\implies 8(y-0)=(x-0)^2
\\\\\\
4(2)(y-0)=(x-0)^2\impliedby \textit{that means, p = 2}$

so... if you notice, the vertex is at h,k and that'd be the origin, 0,0

so...since the directrix is "p" units from the vertex, so it'd be 2 units from 0,0

now, the parabola has an equation with a positive leading term's coefficient, namely the 1/8 is positive, thus, the parabola is opening upwards, and the directrix is "outside" the parabola, so is below the vertex

that puts the directrix 2 units below 0,0

y = -2

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3 years ago

What is the solution of x=2+\sqrt(x-2) x = 2 x = 3 x = 2 or x = 3 no solution

svp [43]

$D:x\geq2\\\\
x=2+\sqrt{x-2}\\
\sqrt{x-2}=x-2\\
x-2=x^2-4x+4\\
x^2-5x+6=0\\
x^2+x-6x+6=0\\
x^2-2x-3x+6=0\\
x(x-2)-3(x-2)=0\\
(x-3)(x-2)=0\\
x=3 \vee x=2$

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3 years ago

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DEFFERENTIATE X^sinx

inna [77]

Answer:

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y = e^(SIN(x)*LN(x))

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y' = (COS(x)·LN(x) + SIN(x)/x)*x^(SIN(x))

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3 years ago

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