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Ivanshal [37]
3 years ago
12

Please help! I cant afford to fail.. PLEASE NO LINKS

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:  The answer that I got was J.

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Suppose you've just deposited $ 2,004 in a bank account which earns an annual rate of return of 12%. How much will you have in t
kondaur [170]

Answer:

you will get back 167$

Step-by-step explanation:

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3 years ago
Input Years, x: 1, 2, 3 Output, Height of tree in feet: 6, 9, 12. Is this discrete or continous?
BartSMP [9]

Answer:

discrete

Step-by-step explanation:

4 0
3 years ago
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Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

\frac{a}{sinA} = \frac{b}{sinB} , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

\frac{a}{sin78} = \frac{18}{sin53} ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = \frac{18sin78}{sin53} ≈ 22.0 ( to the nearest tenth )

(3)

\frac{c}{sinC} = \frac{a}{sinA} , substitute values

\frac{35}{sinC} = \frac{45}{sin134} ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = \frac{35sin134}{45} , then

∠ C = sin^{-1} ( \frac{35sin134}{45} ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

\frac{a}{sinA} = \frac{b}{sinB} , substitute values

\frac{BC}{sin38} = \frac{10}{sin50} ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = \frac{10sin38}{sin50} ≈ 8.0 ( to the nearest tenth )

3 0
3 years ago
Find the value of this expression if x = 4 and y= -2<br> xy / 5
zysi [14]

Step-by-step explanation:

-2×4/5

-8/5

= -1.6

That's the answer

4 0
3 years ago
Read 2 more answers
Help! Based on the given information, what can you conclude and why?
DochEvi [55]

Answer: \triangle HIJ \cong \triangle LKJ

Step-by-step explanation:

Given: ∠H ≅∠L and line HJ congruent to Line JL.

Since, In triangles HIJ and LKJ,

∠H ≅ ∠L

HJ ≅ JL

And, ∠HJI ≅ ∠ LJK

Therefore, By ASA postulate,

Δ HIJ ≅ Δ LKJ

This is why Option first is correct.

Note: Option third ΔHIJ≅ΔJKL is not correct,

Because,  HI≠JK



6 0
3 years ago
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