Answer:
B. 5 + 2(3+2x) = x + 3(x+1)
Step-by-step explanation:
5 + 2(3+2x) = x + 3(x+1)
5 + 6 + 4x = x + 3x + 3
11 + 4x = 4x + 3
4x - 4x = 3 - 11
0 = - 8, which is absurd.
Hence the equation 5 + 2(3+2x) = x + 3(x+1) has no solution.
<span>The next number in this sequence would be 300 because you are multiplying by 10 each time.</span>
Answer:
z=kx/y
zy=kx
zy/x=kx/x ( divided both side by x. to find k)
k=zy/x
k=6×4/3(z=6,y=4,x=3)
k=24/3
k=8
so z=kx/y
z=8×5/2(replace the numbers in the place of variables,k=8,x=5,y=2)
z=40/2
z=20
Adding fractions:
Lets say you have two fractions like 1/2 and 1/3. To add them, you have to make the denominator the same. So we find the least common multiple of 2 and 3, which is 6, so we multiple 1/2 by 3/3 so we have 3/6 without changing the value, and we multiple 1/3 by 2/2 to have 2/6. Then we add the numerators and have 5/6.
Subtraction fractions:
Same thing as adding, just subtracting instead.
Both need to make sure you have the same denominator.
Multiplying fractions:
This is the most simple. All you do is multiply the numerators and the denominators. So if you have 5/6 and 3/4, you multiply the numerators to have 15, the denominators to have 24, and so you have 15/24, simplified to 5/8.
Dividing fractions:
If you have 5/6 divided by 3/4, you flip the 3/4 to 4/3, and you multiply that with 5/6.
Answer:
C
Step-by-step explanation:
Given
x³ + 3x² + 3x + 9 ( factor first/second and third/fourth terms )
= x²(x + 3) + 3(x + 3) ← factor out (x + 3) from each term
= (x² + 3)(x + 3) → C
