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Simora [160]
2 years ago
11

Solve by using trial and error method. 3x = 16​

Mathematics
1 answer:
Paladinen [302]2 years ago
4 0

Answer:

5.3...

..............

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A bookstore had 60 copies of a magazine. Yesterday, it sold 1/3 of them. Today, it sold 1/4 of what remained. How many copies do
lara [203]

Answer:

30

Step-by-step explanation:

1/3 of 60 is 20

40 would be left

1/4 of 40 is 10 so 30 would be left

7 0
3 years ago
Estimate the sum 458+214
sertanlavr [38]
672 is the answer to this question
5 0
3 years ago
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A pyramid with a slant height 4.6 in whose triangular base measures 8 in on each side.Each altitude of the base measures of 6.9
kvasek [131]

Answer:

82.8 in²

Step-by-step explanation:

The surface area a triangular based pyramid :

Base area + 1/2(perimeter * slant height)

Base = 8 inches ; Slant height = 4.6 inches ; altitude of base measure = 6.9 inches

Base area of triangle :

1/2 * base * height

1/2 * 8 * 6.9

4 * 6.9

Base area = 27.6 in²

The perimeter, P = sum of sides ; (s1 + s2 + s3

P = 8 + 8 + 8 = 24 in

Hence,

Surface area = 27.6 in² + 1/2(24*4.6)

Surface area = 27.6 in² + (12 * 4.6) in²

Surface area = (27.6 + 55.2)

Surface area = 82.8 in²

6 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
2 years ago
Read 2 more answers
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