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k0ka [10]
3 years ago
12

ASAP timed test pleasssee

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

x=34 y=99 z=41

Step-by-step explanation:

Mark my answer a brainliest answer

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The polygon below has been divided into four shapes. Which measurements below represent the total area of the polygon?
aliya0001 [1]

Step-by-step explanation:

you have to put the picture of the polygon or we can't answer the question.

3 0
3 years ago
Read 2 more answers
2(3/5x+3). How would I get that answer
Airida [17]

Answer: \frac{6}{5}x + 6

Step-by-step explanation:

       We will use the order of operations, also known as PEMDAS. See attached. Please note that we cannot do what is in the parentheses first because we have a variable, so we will distribute the 2 into it. Since this is an expression, I do not believe we can fully solve for x, but can only simplify.

       Given:

2(3/5x+3)

       Distribute:

2 * (3/5x) + (2 * 3)

6/5x + 6

       Answer:

\frac{6}{5}x + 6

5 0
2 years ago
Hello! :)
bazaltina [42]

Answer:

8x-2y

Step-by-step explanation:

3x4y+5x+2y

Simplify

1 Combine like terms

3x4y+5x+2y

8x-4y+2y

2 Combine like terms

8x-4y+2y

8x-2y

Solution

8x-2y

Hope this helps!

Don't forget to mark me as Brainliest.

4 0
1 year ago
Read 2 more answers
In circle Y, what is mTU?
Marat540 [252]

we know that

The measure of the interior angle is the half-summit of the arcs that comprise it and its opposite

so

63=\frac{1}{2} *(arc \ SR+arc\ TU)\\ \\ 126=55+arc\ TU\\ \\ arc\ TU=126-55\\ arc\ TU=71\ degrees

therefore

the answer is

the measure of arc TU is equal to 71\ degrees

4 0
3 years ago
Read 2 more answers
In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
kow [346]

Answer:

\cos(J) = 0.67

Step-by-step explanation:

Given

\angle K = 90^o

KJ = 65

IK = 72

JI = 97

Required

\cos(J)

The question is illustrated with the attached image.

From the image, we have:

\cos(J) = \frac{KJ}{JI}

This gives:

\cos(J) = \frac{65}{97}

\cos(J) = 0.67010309278

\cos(J) = 0.67 --- approximated

7 0
3 years ago
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