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zvonat [6]
3 years ago
15

When a chemical bond exists between two atoms, an electrical attraction exist between the __________ of each atom and the ______

_____ of the other atom no matter what type of bond you are talking about.
Chemistry
1 answer:
Volgvan3 years ago
4 0

Answer:

c

Explanation:

treswdftgyuiuytredscfvghjk

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A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f
deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

           S = K_{b} \times ln \Omega

where,      S = entropy

             K_{b} = Boltzmann constant

             \Omega = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

     \Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega

                 = 1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)

                 = 1.38 \times 10^{-23} \times (-0.182)

                 = -0.251 \times 10^{-23}

or,             = -2.51 \times 10^{-24}

Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

8 0
3 years ago
A 5.00g piece of metal is heated to 100.0°C, then placed in a beaker containing 20.0 of water at 10.0°C. The temperature of the
Ahat [919]
Answer:

This metal has a specific heat of 0.9845J/ g °C

Explanation:
Step 1: Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)

Step 2: Calculate specific heat
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)

- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-5 * (15-100)(Cpmetal) = 20* (15-10) * (4.184J/g °C =
-5 * (-85)(Cpmetal) = 418.4

Cpmetal = 418.4 / (-5*-85) = 0.9845 J/g °C

This metal has a specific heat of 0.9845J/ g °C
7 0
3 years ago
In this activity, you will plan and conduct an investigation to compare a single property
Alenkinab [10]
Do you still need help with this question?
4 0
3 years ago
A student wants to lift a 50 N backpack off of the floor. Tell me what will happen to the backpack depending on the amount of fo
kirza4 [7]

Answer:

srry agian

Explanation:

6 0
4 years ago
A teacher is discussing several scenarios in the topic of gas law s. Which of the following scenarios will the initial pressure
sukhopar [10]

The scenario whereby the initial pressure is equal to the final pressure is : ( A ) A balloon filled with air is heated from 300k to 600k, causing it to expand and double in size.

<h3>Gay Lussac's law </h3>

Gay Lussac's law states that at constant pressure, the volume of gas is directly proportional to the change in temperature. i.e. V ∝ T. From scenario 1 the change in temperature from 300 K to 600 K shows a 100% increase in temperature which corresponds with the expansion and size doubling of the volume of gas.

Hence we can conclude that The scenario whereby the initial pressure is equal to the final pressure is : ( A ) A balloon filled with air is heated from 300k to 600k, causing it to expand and double in size.

Learn more about Gay Lussac's law : brainly.com/question/24691513

8 0
2 years ago
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