Atomic Number-6
Mass Number-14
        
             
        
        
        
Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics. 
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids. 
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure. 
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids). 
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil. 
 
        
             
        
        
        
Explanation:
 a.  → ?
 → ?




Removing common ions from both sides, we get the net ionic equation:

b.  →
 → 

No precipitation is occuring. 
c.  →
 → 




Removing common ions from both sides, we get the net ionic equation:

d. →
 →




Removing common ions from both sides, we get the net ionic equation:

 
        
             
        
        
        
Answer:
C. Double Replacement
Explanation:
A. Wrong because SR uses a compound and element. This equation is a compound and compound.
B. Wrong because it does not have O2 in the formula. All combustion reactions must have O2. 
C. Correct because it is a compound reacting with a compound. 
D. Wrong because the reactants did not form a single product. ex. (x + y > xy)
E. Wrong because the equation did not start with a single compound and break down. ex. (xy > x + y)
 
        
             
        
        
        
Answer:
4.89 mol
Explanation:
Step 1: Write the balanced equation
This is a double displacement reaction.
3 CaSO₄ + 2 AIP ⇒ Ca₃P₂ + AI₂(SO₄)₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CaSO₄ to AlP is 3:2.
Step 3: Calculate the moles of AlP needed to react with 7.33 moles of CaSO₄
We will use the previously established molar ratio.
7.33 mol CaSO₄ × 2 mol AlP/3 mol CaSO₄ = 4.89 mol AlP