In this activity, you will plan and conduct an investigation to compare a single property

With the kinetic energy of a sample increases the____ will also increase

klemol [59]

Answer:

Its Temperature.

Explanation:

Kinetic energy is the energy possessed by a body while in motion. Potential energy on the other hand is the energy possessed by a body based on its position.
Kinetic energy of a body is determined by the equation; K.E = 3RT/2;
From the equation, kinetic energy is directly proportional to the temperature of the system and therefore an increase in the kinetic energy of a sample causes an increase in temperature of the system.

4 0

2 years ago

Consider the following chemical equilibrium:

jok3333 [9.3K]

Answer:

Kc = [CH₄] / [H₂]²

Kp = [CH₄] / [H₂]² * (0.082*T)^-1

Explanation:

Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.

<em>Pure solids and liquids are not taken into account in an equilibrium</em>

Thus, for the reaction:

C(s)+ 2H₂(g) ⇌ CH₄(g)

Equilibrium constant is:

Now, using the formula:

Kp = Kc* (RT)^Δn

<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>

Replacing:

<em />

4 0

3 years ago

Which functional group does the molecule below have?

makvit [3.9K]

Answer:

B

Explanation:

7 0

1 year ago

How many gram of gaseous carbon dioxide can be absorbed or reacted by 2kg of lithium hydroxide?

Greeley [361]

Answer:

shuuuuuuuuuuuuuuuuuuuuuuush

Explanation:

shush suuush shuuush

5 0

3 years ago

Pressure cookers allow food to cook faster because the higher pressure inside the pressure cooker increases the boiling temperat

KonstantinChe [14]

Answer:

$\boxed{\text{139 $\, ^{\circ}$C}}$

Explanation:

The question is asking, "At what temperature does the vapour pressure of water equal 3.4 atm?"

To answer this question, we can use the Clausius-Clapeyron equation:

$\ln \left (\dfrac{p_{2}}{p_{1}} \right) = \dfrac{\Delta_{\text{vap}}H}{R} \left(\dfrac{1 }{ T_{1} } - \dfrac{1}{T_{2}} \right)$

Data:

p₁ = 1 atm; T₁ = 373.15C

p₂ = 3.4atm; T₂ = ?

R = 8.314 J·K⁻¹mol⁻¹

$\Delta_{\text{vap}}H = \text{39.67 kJ//mol}$

(The enthalpy of vaporization changes with temperature. Your value may differ from the one I chose.)

Calculation:

$\begin{array}{rcl}\ln \left (\dfrac{p_{2}}{p_{1}} \right)& = & \dfrac{\Delta_{\text{vap}}H}{R} \left( \dfrac{1}{T_{1}} - \dfrac{1}{T_{2}} \right)\\\\\ln \left (\dfrac{3.4}{1} \right)& = & \dfrac{39670}{8.314} \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\\ln3.4 & = & 4771 \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\1.224 & = & 12.78 - \dfrac{4771}{T_{2}}\\\\\dfrac{4771}{T_{2}} & = & 11.56\\\\\end{array}$

$T_{2} & = & \dfrac{4771}{11.56} = \text{412.6 K} = \textbf{139 $\, ^{\circ}$C}\\\\\text{The maximum temperature is } \boxed{\textbf{139 $\, ^{\circ}$C}}$

7 0

3 years ago