Answer:
a) If the solvent-solute interactions in a mixture are <u>stronger than</u> the solvent-solvent interactions and the solute-solute interactions, a homogeneous solution forms.
b) If the solvent-solute interactions in a mixture are <u>weaker than</u> the solvent-solvent interactions and the solute-solute interactions, the formation of a homogeneous solution is uncertain.
Explanation:
The solubility of solute in given solvent mainly depends upon the intermolecular interactions between the solvent and the solute. If the solute is surrounded and solvated by the solvent then the solute will dissolve in that solvent. Therefore, in order to dissolve the solute must form stronger interactions with the solvent as compared to the solute solute interactions or solvent solvent interactions.
Example:
When NaCl is added to water the partial negative oxygen of water is attracted to Na⁺ of NaCl and the partial positive hydrogen of water is attracted to Cl⁻ of NaCl. These new interactions between the NaCl ions and water are stronger than the interactions between water molecules and NaCl molecules themselves hence, results in solubility of NaCl in water.
On the other hand, if NaCl is added to Hexane (C₆H₁₄) it fails to make strong interactions with the solvent molecules resulting in insolubility of NaCl in hexane.
Answer:
2445 L
Explanation:
Given:
Pressure = 1.60 atm
Temperature = 298 K
Volume = ?
n = 160 mol
Using ideal gas equation as:

where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 08206 L.atm/K.mol
Applying the equation as:
1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K
<u>⇒V = 2445.39 L</u>
Answer to four significant digits, Volume = 2445 L
Dalton's law states that the total pressure of a mixture of non-interacting gases is equal to the sum of their partial pressures.
In this case,


You pretty much answered your own question haha
hotter stars die more quickly because, well, they're hotter than the sun
providing heat takes a lot of energy.
<em>Answer:</em>
- The molarity of ammonia will be 2.88 M.
<em>Chemical equation</em>
HCl + NH3 ------> NH4Cl
First of calculate the moles of HCl
mole of HCl = Molarity × Vol (L)
mole of HCl = 0.800× 0.018 = 0.014 mole
As the in balance chemical, moles of HCl and NH3 areequal
so
moles of NH3= 0.014
Molarity of NH3 = moles ÷ V(L) = 0.014/0.005 = 2.88 M
<em>Result</em>:
- The molarity of ammonia will be 2.88 M.