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10th
Maths
Pair of Linear Equations in Two Variables
Algebraic Solution of a Pair of Linear Equations
Solve: 3x + 4y = 10,2x - 2y...
MATHS
Asked on December 27, 2019 byShweta Rudravaram
Solve: 3x+4y=10,2x−2y=2 by the method of elimination.
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ANSWER
3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
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3x+4y=10
3x−3y=3
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7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x=36=2
Hence x=2,y=1.
there are 18 marbles all together
4 are red
18÷4= 4.5
percent 4.5%
fraction 4 1/2
decimal 4.5
I'm not sure about the second hald but I hope this helped ^^
Steps to solve:
15 + 2a = 35
~Subtract 15 to both sides
2a = 20
~Divide 2 to both sides
a = 10
Best of Luck!
35
Area of rectangle
21m^2
Area of one triangle
divide length of 7 by 2 (3.5)
gives you length b (unknown side that is not hypotenuse)
then multiply by width of triangle (4)
3.5 * 4 = 14
and in this situation there is no need to divide by two, because you essentially have one full square from both the triangles. this only works when both triangles are the same.
add the area of the rectangle
14+21= 35
35m^2
First number: x = 19
Second number: Y = -5
x + 2y = 9
2x + y = 33
