Answer:
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Answer:
0.1587 = 15.87% probability that a person will wait for more than 9 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The mean waiting time is 6 minutes and the variance of the waiting time is 9.
This means that 
Find the probability that a person will wait for more than 9 minutes.
This is 1 subtracted by the p-value of Z when X = 9. So



has a p-value of 0.8413.
1 - 0.8413 = 0.1587
0.1587 = 15.87% probability that a person will wait for more than 9 minutes.
Answer:
5
Step-by-step explanation:
f(-1)=2(-1)+7
f(-1)=-2+7
f(-1)=5
Put it into the photomath app. it gives answer and steps.
Answer:
116.3, 41.05
Step-by-step explanation:
Using the growth rate formula
Final = initial(1 + rate)^n
Rate = 2% = 0.02
n = number of years
Carry capacity = 100%( the original state before the disease)=final
100% = 1
1 = 0.1 ( 1+0.02)^n
10 = (1.02) ^n
Log 10/ Log 1.02 = 116.3 = n
b) initial rate doubled = 0.02*2 (2%*2) = 0.04
Initial population doubled by importation = 0.1 *2 = 0.2
Again, 1 = 0.2 ( 1+0.04)^n
5 = 1.04^n
Log 5/ Log 1.04 = 41.05 = n