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3 years ago

11

What is the distance between -3 and 5 on a real number line

2 answers:

attashe74 [19]3 years ago

8 0

The distance between -3 and 0 is positive 3 , and the distance between 0 and 5 is 5, add 5 and 3 together to get a distance of 8

larisa86 [58]3 years ago

7 0

The distance between -3 and 5 is 7. If you were to include -3 and 5 into it, then it would be 9. But the distance BETWEEN is 7.

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Kira is a software saleswoman. Her base salary is $1600, and she makes an additional $60 for every copy of "English is Fun" she

Alchen [17]

Answer:

P = 1600 + 60N; $3,340

Step-by-step explanation:

Since we know she gets $1,600 as a base, and $60 <em>each book</em>, we have to add a variable to 60 to show how many books she sells. Your first equation will be P (which is the total) = 1,600 + 60N. Now, we have to replace N with 29. You now have P = 1,600 + 60(29) = 1,600 + 1,740 = $3,340. That's your answer!

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3 years ago

Read 2 more answers

Please help, I I beg you please

Tatiana [17]

Answer:

<em>The volume of the cube is </em> $\mathit{\frac{27}{z^3x^{9}}}$ <em>cu in.</em>

Step-by-step explanation:

<u>The Volume of a Cube</u>

Let's have a cube of side length a. The volume of the cube is:

$V=a^3$

The cube of the image has a side length of

$\displaystyle a=\frac{3x^{-3}}{z}\ inches$

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

$\displaystyle a=\frac{3}{zx^{3}}\ inches$

Now find the volume:

$\displaystyle V=\left(\frac{3}{zx^{3}}\ inches\right)^3$

Applying the exponents:

$\displaystyle V=\frac{3^3}{z^3x^{9}}\ inches^3$

$\displaystyle V=\frac{27}{z^3x^{9}}\ inches^3$

The volume of the cube is $\mathbf{\frac{27}{z^3x^{9}}}$ cu in.

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3 years ago

Convert 13 to fifths.<br> Write your answer as a fraction.

Zina [86]

Answer:

65/5

Step-by-step explanation:

You just need to multiply 13 by 5.

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