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3 years ago

What is 3.1 as a mixed fraction in simplest form

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

5 0

3.1 in fraction form is 3 1/10 or if you cant use mixed numbers, its 31/10

zmey [24]3 years ago

3 0

The word form of 3.1 is three and one tenth. "Three and one tenth" could also be a mixed number, so all we do is get the mixed number "three and one tenth":
$3 \frac{1}{10}$

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Solve the equation for y. 4.2x-1.4y=2.1

mr Goodwill [35]

Subtract 2.1 from both sides:

$4.2x-1.4y-2.1=0$

Add 1.4y to both sides:

$4.2x-2.1=1.4y$

Of course, we can rewrite this as

$1.4y=4.2x-2.1$

Divide both sides by 1.4

$y = \dfrac{4.2}{1.4}x - \dfrac{2.1}{1.4} = 3x - 1.5$

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3 years ago

i know that it’s B, and i’ve explained that it’s because there is no correlation among the data points but for some reason it’s

Elina [12.6K]

I think the answer would be C

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I may be wrong so take it with a grain of salt

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2 years ago

Given parallelogram ABCD with<br> m B = 5x and mC = 3x+4.<br> Find the number of degrees in mD

emmainna [20.7K]

Answer: X=22

Step-by-step explanation:

8 0

2 years ago

Help me please I beg

likoan [24]

Answer:

a) x=25+0.06y

b)x=25+0.06*30=£26.80

c)x=25+0.06*200=£37

d)x=25+0.06y ; 43=25+0.06y ; 43-25=0.06y ; 18=0.06y ; y=18÷0.06 ; y=300 messages

Step-by-step explanation:

aaaaaa hope theyre correct

7 0

2 years ago

Verify the following identity:

Paraphin [41]

We will simplify the left hand side of the equation to look like the right

$\displaystyle \frac{1-sin(t)}{cos^{2}(t)} + \frac{1}{1 - sin(t)}$

taking the LCM

$\displaystyle \frac{[1-sin(t)]^{2} + cos^{2}(t)}{[cos^{2}(t)][1 - sin(t)]}$

expanding the binomial in the numerator

$\displaystyle \frac{[1 + sin^{2}(t) - 2sin(t) + cos^{2}(t)]}{[cos^{2}(t)][1 - sin(t)]}$

Since sin²x + cos²x = 1

$\displaystyle \frac{[2 - 2sin(t)]}{[cos^{2}(t)][1 - sin(t)]}$

factoring out the 2 from the numerator

$\displaystyle \frac{2[1 - sin(t)]}{[cos^{2}(t)][1 - sin(t)]}$

1-sin(t) will cancel out

$\displaystyle \frac{2}{cos^{2}(t)}$

since cos²(t) = 1/(sec²(t))

$2 sec^{2}(t)$

which is equal to the right hand side of our given equation.

So we verified the identity!

5 0

2 years ago

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