Subtract 2.1 from both sides:

Add 1.4y to both sides:

Of course, we can rewrite this as

Divide both sides by 1.4

I think the answer would be C
As it is basically a straight line so there wouldn't be necessary for there to be a scatter diagram for it.
I may be wrong so take it with a grain of salt
Answer: X=22
Step-by-step explanation:
Answer:
a) x=25+0.06y
b)x=25+0.06*30=£26.80
c)x=25+0.06*200=£37
d)x=25+0.06y ; 43=25+0.06y ; 43-25=0.06y ; 18=0.06y ; y=18÷0.06 ; y=300 messages
Step-by-step explanation:
aaaaaa hope theyre correct
We will simplify the left hand side of the equation to look like the right

taking the LCM
![\displaystyle \frac{[1-sin(t)]^{2} + cos^{2}(t)}{[cos^{2}(t)][1 - sin(t)]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5B1-sin%28t%29%5D%5E%7B2%7D%20%2B%20cos%5E%7B2%7D%28t%29%7D%7B%5Bcos%5E%7B2%7D%28t%29%5D%5B1%20-%20sin%28t%29%5D%7D)
expanding the binomial in the numerator
![\displaystyle \frac{[1 + sin^{2}(t) - 2sin(t) + cos^{2}(t)]}{[cos^{2}(t)][1 - sin(t)]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5B1%20%2B%20sin%5E%7B2%7D%28t%29%20-%202sin%28t%29%20%2B%20cos%5E%7B2%7D%28t%29%5D%7D%7B%5Bcos%5E%7B2%7D%28t%29%5D%5B1%20-%20sin%28t%29%5D%7D)
Since sin²x + cos²x = 1
![\displaystyle \frac{[2 - 2sin(t)]}{[cos^{2}(t)][1 - sin(t)]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5B2%20-%202sin%28t%29%5D%7D%7B%5Bcos%5E%7B2%7D%28t%29%5D%5B1%20-%20sin%28t%29%5D%7D)
factoring out the 2 from the numerator
![\displaystyle \frac{2[1 - sin(t)]}{[cos^{2}(t)][1 - sin(t)]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%5B1%20-%20sin%28t%29%5D%7D%7B%5Bcos%5E%7B2%7D%28t%29%5D%5B1%20-%20sin%28t%29%5D%7D)
1-sin(t) will cancel out

since cos²(t) = 1/(sec²(t))

which is equal to the right hand side of our given equation.
So we verified the identity!