The solution to system is x = 0 and y = -1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-8x + 2y = -2 ----------- eqn 1
4x + 4y = -4 ---------- eqn 2
We have to solve the system of equations
We can solve the equations by elimination method
<em><u>Multiply eqn 2 by 2</u></em>
8x + 8y = -8 ------ eqn 3
<em><u>Add eqn 1 and eqn 3</u></em>
-8x + 2y = -2
8x + 8y = -8
( + ) ---------------
0x + 2y + 8y = -2 - 8
10y = -10
Divide both sides by 10
y = -1
<em><u>Substitute y = -1 in eqn 1</u></em>
-8x + 2(-1) = -2
-8x - 2 = -2
-8x = -2 + 2
x = 0
Thus the solution to system is x = 0 and y = -1
Answer:
6. 1.01 x -10^5
7. 6 x -10^14
8. 550,000
9. 60,700,000
10. 0.000204
11. 0.0004
12. 7,000,000,000,000 > 3,500,000,000
7,000,000,000,000 (or 7 x 10^12) is greater by 2,000 times
15. 10^3 and 10^4
Answer:
{3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}
Step-by-step explanation:
54 = 1×54 = 2×27 = 3×18 = 6×9
Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...
- 3¢ and 28¢
- 4¢ and 19¢
- 7¢ and 10¢
Answer:
-3, -1, 1, 7
Step-by-step explanation:
took the test. Now i have to retake it ;(
