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Bas_tet [7]
3 years ago
6

Can someone help of you dont know dont answer​

Mathematics
2 answers:
AfilCa [17]3 years ago
6 0
For question 2 the answer is: B and for question 3 the answer is: D
ohaa [14]3 years ago
6 0

Answer:

the answer is A for both of the questions

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8x-3y<4 and 9x+2y<-1 is (5,-5) a solution of the system yes or no
azamat

For this case we have the following system of inequalities:

8x-3y

We must verify if the point(x, y) :( 5, -5) is a system solution

Inequality 1:

8 (5) -3 (-5)

Inequality is not met!

Thus, the given point is not a system solution.

Answer:

The point is not a system solution.

4 0
3 years ago
PLEASE HELP ANSWER WITH ALL STEPS PLS
kupik [55]
Hello.

Question 4:

-2.34n = -12.168
Divide both sides by -2.34;

n = 5.2 is your answer to #4 (Answer choice "C.)"

For Question 5:

-8c = 56
Divide both sides by -8 to solve for c;

c = -7 (remember your signs!) is your answer for #5 (Answer choice "C.)"

\frac{n}{-12.168} = -2; To solve for this, we need to multiply both sides by -12.168 to isolate and solve for our variable.

\frac{n}{-12.168} = -2; Multiply by -12.168

n = 24.336 (A negative multiplied by a negative results in a positive product.);

Your answer for #3 is n = 24.336 (Answer choice "B.)")

I hope this helps!
6 0
4 years ago
Read 2 more answers
Which expression is equivalent to this polynomial expression? (2x^2 – 3y^2)(4x^4 + 6x^2y^2 +9y^4)​
NeX [460]

Answer:

26 {x}^{6}  - 18 {x}^{2}  {y}^{4}  - 27 {x}^{4}  {y}^{2}

Step-by-step explanation:

click the link for alot more explanation, I'm tried typing

https://photomath.net/s/l5LVxj

4 0
3 years ago
What type of problems can always be solved using the law of cosines or sines?
laila [671]
Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure. 

OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!
4 0
3 years ago
Camille is starting an exercise program. During the first week, she walked 3/4 mile every day. Every week she increased the dist
Oksanka [162]

Answer:

E

Step-by-step explanation:

Distance = 1/3(week -1) + ¾

= 1/3(7) + ¾

= 7/3 + 3/4

= 28/12 + 9/12

= 37/12 miles

4 0
3 years ago
Read 2 more answers
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