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postnew [5]
3 years ago
12

How do you determine two angles which are coterminal to the given angles ?

Mathematics
1 answer:
Julli [10]3 years ago
7 0

Answer:

Coterminal Angles are angles who share the same initial side and terminal sides. Finding coterminal angles is as simple as adding or subtracting 360° or 2π to each angle, depending on whether the given angle is in degrees or radians. There are an infinite number of coterminal angles that can be found.

Step-by-step explanation:

i hope this helped you :)

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What is the value of x? <br> sin41°=cos x<br> Enter your answer in the box. <br> x = °
creativ13 [48]

Answer:

  x = 49°

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement:

  x = 90° -41° = 49°

5 0
3 years ago
Which of the following expression expressions is equivalent to cos3x/sinxcosx?
77julia77 [94]
Correct Option:
Option B

Solution:
The given expression is:

\frac{cos(3x)}{sin(x)cos(x)}

cos(3x) can be written as cos(2x +x). Expanding it, we get:

cos(3x) = cos(2x+x) \\  \\ &#10;cos(3x) =cos(2x)sin(x)-sin(2x)cos(x)

Using this value of cos(3x) in given equation, we get:

\frac{cos(3x)}{sin(x)cos(x)} \\  \\ &#10;= \frac{cos(2x)sin(x)-sin(2x)cos(x)}{sin(x)cos(x)} \\  \\ &#10;= \frac{cos(2x)sin(x)}{sin(x)cos(x)}- \frac{sin(2x)cos(x)}{sin(x)cos(x)}  \\  \\ &#10;= \frac{cos(2x)}{cos(x)} - \frac{sin(2x)}{sin(x)} \\  \\ &#10;=sec(x)cos(2x)-csc(x)sin(2x)
8 0
3 years ago
Read 2 more answers
Please helppp!!!!
Nostrana [21]

Answer:

ok more info please and I can help

8 0
3 years ago
A competitive cliff diver jumps into
fredd [130]

Answer:

2.25 seconds

Step-by-step explanation

d=16t^{2}

d=81 feet\\t=?

Because you know what distance equals you can plug it into the equation

81=16t^{2}

From there you can solve by dividing the 16 over and then square rooting.

\frac{81}{16}=t^{2}

5.0625=t^{2}

You take the square-root to get rid of t^{2}

\sqrt{5.0625} =\sqrt{t}^{2}

t=2.25

8 0
3 years ago
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Murrr4er [49]
I think compatible numbers
4 0
3 years ago
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