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2 years ago

Pratctice and Solving Solve each equation with variables on both sides 1. 6x - 2 = x + 13

Mathematics

2 answers:

IrinaK [193]2 years ago

8 0

Answer:

x=3

Step-by-step explanation:

6x - 2 = x + 13

subtract 1x from both sides

5x - 2 = 13

isolate the 5x by adding 2 to both sides

5x = 15

finnaly devide both by 5

x = 3

Rus_ich [418]2 years ago

7 0

Answer:

-7

Step-by-step explanation:

1.6x-2=x+13

+1.6x +1.6x

-2=2.6x+13

-13 -13

-15=2.6x

(2.6 divided by 2.6)

(-15 divided by 2.6 is -7)

answer:-7

Sorryyyyy its hard to explain

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3 years ago

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3 years ago

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Rudiy27

Answer:

Step-by-step explanation:

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In number 1 the set up would look like this

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3 years ago

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3 years ago

For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?

irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

$=\frac{2x}{x^2-9}$

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression

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3 years ago

Pratctice and Solving Solve each equation with variables on both sides 1. 6x - 2 = x + 13​

Pratctice and Solving Solve each equation with variables on both sides 1. 6x - 2 = x + 13