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Kryger [21]
3 years ago
13

Pratctice and Solving Solve each equation with variables on both sides 1. 6x - 2 = x + 13​

Mathematics
2 answers:
IrinaK [193]3 years ago
8 0

Answer:

x=3

Step-by-step explanation:

6x - 2 = x + 13

subtract 1x from both sides

5x - 2 = 13

isolate the 5x by adding 2 to both sides

5x = 15

finnaly devide both by 5

x = 3

Rus_ich [418]3 years ago
7 0

Answer:

      -7

Step-by-step explanation:

     1.6x-2=x+13

   +1.6x      +1.6x

          -2=2.6x+13

          -13        -13

          -15=2.6x

(2.6 divided by 2.6)

(-15 divided by 2.6 is -7)

answer:-7

Sorryyyyy its hard to explain

             

         

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the measure of one angle of an isosceles trapezoid is x and the angle opposite it is x+20,what is the value of x​
lakkis [162]

Answer:

X=80

Step-by-step explanation:

I suppose the graph will be like this:

Since isosceles trapezoid, red lines are parallel.

X+x+20= 180

2x+20=180

2x=160

X=80

5 0
3 years ago
You want to draft a four ­player tennis team. There are eight players to choose from. How many different teams can you form?
Butoxors [25]

We want to make a 4 players team, and there are total 8 players. As we know the order of selection does not matter in a team of players, only the combination of players matters.

So we would use concept of Combinations and It will be choose 4 out of 8 players.

The formula for Combination is given as follows :-

nCr = \frac{n!}{r!*(n-r)!} \\\\
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8C4 = \frac{8!}{4!*(8-4)!} = \frac{8!}{4!*4!} \\\\
8C4 = \frac{8*7*6*5*4*3*2*1}{(4*3*2*1)*(4*3*2*1)} = \frac{8*7*6*5}{4*3*2*1} =\frac{1,680}{24} = 70 \;combinations

Hence, Total number of different teams = 70 combinations.

4 0
3 years ago
Solve each equation by taking square roots<br><br> 2n^2 -8=-33
densk [106]
2n^2 -8=-33 

&#10;2n^2=-33+8&#10; &#10;    Add \ 8 \ to \ both \ sides 

2n^2=-25 

n^2=- \dfrac{25}{2}   Divide \ both \ sides \ by \ 2 

n=+ \sqrt{ -\dfrac{25}{2} }  <span> Take \ the \ square \ root \ of \ both \ sides  
</span>
n=+ \sqrt{ \dfrac{5i}{ \sqrt{2}}}
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lora16 [44]

Answer:

oh god

you posted this question 5times already xd

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4 0
3 years ago
Read 2 more answers
Please Help!!!!!!! Geometry Help Please!!
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B. same angle, congruent
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e. congruent angles
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h.
4 0
3 years ago
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