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AVprozaik [17]
3 years ago
9

Help confused thanks

Mathematics
1 answer:
sukhopar [10]3 years ago
3 0
\left[\begin{array}{cc}Juice&Water\\1&3\\2&6\\3&9\\4&12\\\end{array}\right]

w=3j
36=3j
j=\frac{36}{3}=12cups
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masha68 [24]
<span>Simplifying X + 12 = 30
 Reorder the terms: 12 + X = 30
 Solving 12 + X = 30
 Solving for variable 'X'.
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 Add '-12' to each side of the equation. 12 + -12 + X = 30 + -12
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6 0
3 years ago
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Can someone help me with this
aleksandrvk [35]

Answer:

the answer to the second question is h^9

Step-by-step explanation:

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5 0
3 years ago
Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each bea
xz_007 [3.2K]

Answer:

To make a profit of at least $500 she must sell at least 12 necklaces

Step-by-step explanation:

Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each beaded necklace was $15. If Joyce sells the beaded necklaces at $35 each then we have to find beaded necklaces she sell to make a profit of at least $500.

The costs side of the equation, we have:

Let no. of necklaces that she sell are x

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Now, Joyce sells the beaded necklaces at $35 each. Therefore, selling price will be $35x

To make a profit of at least $500 the equation can be written as

95+15x+500\leq35x

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Hence,  to make a profit of at least $500 she must sell at least 12 necklaces



7 0
3 years ago
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Bumek [7]
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8 0
3 years ago
I need an accurate answer please
kotykmax [81]

x = –6

Solution:

Given expression is \sqrt[3]{x-2}+5=3.

Step 1: Isolate the radical by subtracting 5 from both sides of the equation.

\Rightarrow\sqrt[3]{x-2}+5-5=3-5

\Rightarrow\sqrt[3]{x-2}=-2

Step 2: Cube both sides of the equation to remove the cube root.

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Cube and cube root get canceled in left side of the equation.

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Step 3: To solve for x.

Add 2 on both sides of the equation.

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\Rightarrow\ x=-6

Hence the solution is x = –6.

6 0
3 years ago
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