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2 years ago

Please help, I need Answers quickly.

Mathematics

2 answers:

Deffense [45]2 years ago

8 0

Add 6.5 to both sides

D=-0.7

A

snow_lady [41]2 years ago

6 0

The answer is definitely -0.7

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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?

timama [110]

The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).

4 0

2 years ago

Which statement is true ?

GenaCL600 [577]

Answer:

Step-by-step explanation:

A complementary angle is an angle at 90 degrees and is formed by 2 angles.

3 0

2 years ago

Please help me I don’t understand this

Lyrx [107]

When you're given a point and the slope of a line, it is often easiest to write its equation in point-slope form.

This is $y-y_1=m(x-x_1)$ , where $(x_1,y_1)$ is the ordered pair for the point you are given and m is the slope.

Here, you would write $y-8=-3(x-7)$ . Then, you simplify to get to slope-intercept form, which is $y = mx+b$ , where b is the y-intercept.

$y-8=-3(x-7) \\ y=-3x+29$

The correct answer is A.

6 0

3 years ago

Use the figure below to find the exact values of the double angles.

scZoUnD [109]

Right away, we know that

$\cos\beta=\dfrac{16}{20}=\dfrac45$

which means

$\sin\beta=\sqrt{1-\cos^2\beta}=\dfrac35$

Then

$\cos\beta=\cos2\left(\dfrac\beta2\right)=\cos^2\dfrac\beta2-\sin^2\dfrac\beta2$

$\sin\beta=\sin2\left(\dfrac\beta2\right)=2\sin\dfrac\beta2\cos\dfrac\beta2$

Let $x=\cos\dfrac\beta2$ and $y=\sin\dfrac\beta2$ . Then

$\begin{cases}\dfrac45=x^2-y^2\\\\\dfrac35=2xy\end{cases}\implies\begin{cases}\cos\dfrac\beta2=\dfrac3{\sqrt{10}}\\\\\sin\dfrac\beta2=\dfrac1{\sqrt{10}}\end{cases}$

from which we find

$\tan\dfrac\beta2=\dfrac{\sin\frac\beta2}{\cos\frac\beta2}=\dfrac13$

You can use the same ideas above to find the trig ratios for $\dfrac\alpha2$ , starting from the given fact that $\sin\alpha=\dfrac{16}{20}=\dfrac45$ .

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2 years ago

i am greater than one-fourth but less than four tenths . i am a decimal rounded to the hundreds place. what number am i

artcher [175]

(0.25,0.40). Written in interval notation. It can be any number greater than 1/4 but less that 4/10.

3 0

2 years ago

Read 2 more answers