Find the range for the measure of the third side of a triangle given the measures 5 and 9 for two of its sides.
1 answer:
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The completely factored equation is (a²b - 5)(4a²b - 1)
<h3>How to factor equation?</h3>4a⁴b² - 21a²b + 5 = 0
let's expand the equation
Therefore,
4a⁴b² - 21a²b + 5 = 0
4a⁴b² - 20a²b - a²b + 5 = 0
Rearrange the equation
4a⁴b² - a²b - 20a²b + 5 = 0
Let's factorise the equation
4a⁴b² - a²b - 20a²b + 5 = 0
a²b(4a²b - 1) - 5(4a²b - 1) = 0
Therefore, the completely factored equation is as follows:
a²b(4a²b - 1) - 5(4a²b - 1) = 0
(a²b - 5)(4a²b - 1)
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Answer:
![a=2[d-V_0t]/t^2=2d/t^2-2v_0/t](https://tex.z-dn.net/?f=a%3D2%5Bd-V_0t%5D%2Ft%5E2%3D2d%2Ft%5E2-2v_0%2Ft)
Explanation:
Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).
1) displacement formula:
2) Subtract the term Vot from both sides:
3) Multiply both sides by 2:
4) Divide both sides by t²
![2[d-V_0t]/t^2=a](https://tex.z-dn.net/?f=2%5Bd-V_0t%5D%2Ft%5E2%3Da)
So, you have obtainded:
a = 2[d - Vo×t] / t²
Yet, you can arrange it in different ways. For example, you might separate into two terms:
Explanation:
Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).
1) displacement formula:
2) Subtract the term Vot from both sides:
3) Multiply both sides by 2:
4) Divide both sides by t²
So, you have obtainded:
a = 2[d - Vo×t] / t²
Yet, you can arrange it in different ways. For example, you might separate into two terms: