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Norma-Jean [14]

2 years ago

13

What is 2x-15+21= -18

2 answers:

Brrunno [24]2 years ago

7 0

Hopes this helps:

Answer: x = -12

How I know I use this app called Cymath.

kirill115 [55]2 years ago

4 0

Answer:

2x - 15 +21 = -18

2x + 6 + 18 = 0

2x + 24 =0 ...it is a linear equation

if u want to solve for X then..

2x = -24

X = <u>-</u><u> </u><u>24</u>

2

X = -12

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Sergio [31]

Answer:

310 pages in book = 100%

Step-by-step explanation:

5 0

2 years ago

Solve this and get 12 points

Pachacha [2.7K]

Answer:

9

Step-by-step explanation:

First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:

$x=\frac{13+-16+6}{3}=3/3=1$

<em>y</em> is the cube root of 8. Thus:

$y=\sqrt[3]{8}=2$

So:

$x^2+y^3\\=(1)^2+(2)^3\\=1+8=9$

5 0

2 years ago

Read 2 more answers

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

2 years ago

Read 2 more answers

La funcion que representa el beneficio obtenido por una empresa si vende x unidades de uno de sus productos es f(x)= -70x^2+2800

DerKrebs [107]

Answer:

$20$

Step-by-step explanation:

La función es

$f(x)=-70x^2+2800x-45000$

Diferenciando con respecto a $x$ obtenemos

$f'(x)=-140x+2800$

Igualar con cero

$0=-140x+2800\\\Rightarrow x=\dfrac{2800}{140}\\\Rightarrow x=20$

Doble derivada de la función

$f''(x)=-140$

Entonces, la función es máxima cuando el número de unidades vendidas, $x=20$ ,

3 0

2 years ago

-10+3x=8 solve for X what is X?

vfiekz [6]

x=6

so the answer is 6

3 0

2 years ago

Read 2 more answers