For year 2 - 7:
100% + 5.5%
= 105.5%
= 1.055
Year 1: $900
Year 2: 1.055 x $900 = $949.5
Year 3: 1.055 x $949.5 = $1001.72
Year 4: 1.055 x $1001.72 = $1056.81
Year 5: 1.055 x $1056.81 = $1114.93
Year 6: 1.055 x $1114.93 = $1240.95
Year 7: 1.055 x $1240.95 = $1309.20
Total rent for 7 years
= $(900 + 949.5 + 1001.72 + 1056.81 + 1114.93 + 1240.95 + 1309.20) x 12 months
= $90877.32
Answer:
the average number of car(s) in the system is 1
Step-by-step explanation:
Given the data in the question;
Arrival rate; λ = 2.5 cars per hour
Service time; μ = 5 cars per hour
Since Arrivals follows Poisson probability distribution and service times follows exponential probability distribution.
Lq = λ² / [ μ( μ - λ ) ]
we substitute
Lq = (2.5)² / [ 5( 5 - 2.5 ) ]
Lq = 6.25 / [ 5 × 2.5 ]
Lq = 6.25 / 12.5
Lq = 0.5
Now, to get the average number of cars in the system, we say;
L = Lq + ( λ / μ )
we substitute
L = 0.5 + ( 2.5 / 5 )
L = 0.5 + 0.5
L = 1
Therefore, the average number of car(s) in the system is 1
The answer will be 39.71 PI mcuboc.
It is because 1.9squared is 3.61
3.61 multiplied by 11 is 39.71 PI meter cubic.
Divide 60 by 3 okay .......
Answer:
$79.05
Step-by-step explanation:
Multiply 93 times 15%, which gets you $13.95.
Then subtract 13.95 from the 93 (93 - 13.95).