![\left[\begin{array}{ccc}The&Answer&Should\\Be&The&Second\\Option&Good&bye\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DThe%26Answer%26Should%5C%5CBe%26The%26Second%5C%5COption%26Good%26bye%5Cend%7Barray%7D%5Cright%5D)
------------------------------------------
Answer:
D
Step-by-step explanation:
We can solve this particular problem entirely by elimination. First, notice, that our inequality simply says the left side is <em>less than</em> the right, not <em>less than or equal to</em>. If it were less than or equal to the value on the right, it would include all of the points on the boundary line, and we'd indicate this with a solid line. In our situation, the left side is never <em>equal</em> to the right, so we'd use a dotted line to draw our boundary line. Only B and D fit the bill.
So between B and D, which one represents
? Well, setting the two sides equal to each other, we'd get the equation for a line. If (x, y) is a point on that line, then, what does mean when we say the side with y on it is less than the side with the x on it? It means we'd have to <em>decrease </em>the y value of a point on the line, which would give us a point <em>below </em>the line. So our graph has to show <em>every point below the line 4y + 8 = -3x</em>, and the only answer that represents this situation is D
Answer:
6
Step-by-step explanation:
I think its D. im not positive tho
Step-by-step explanation:
2x+3=x+x+3
add the X's on the right side together.
2x+3=2x+3
subtract 2x from both sides
3=3
subtract 3 from both sides
0=0
the statement is true for any value of x