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kenny6666 [7]
2 years ago
10

Math problem graphing pls help ill give u brainiest

Mathematics
2 answers:
Arturiano [62]2 years ago
5 0

Answer:

Step-by-step explanation:

I multiplied every coordinate by 1/3

The coordinates are in the attachment below

creativ13 [48]2 years ago
3 0
Just multiply every coordinate by 1/3
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8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the
marissa [1.9K]

Answer:

\sf y = \bold -\frac{2}{5} x -3

Explanation:

part A identification for slope:

\sf 2x + 5y = 15

\sf 5y = -2x + 15

\sf y = \frac{-2x + 15}{5}

\sf y = -\frac{2 }{5} x+3

comparing with slope intercept form: y = mx + b

we can find that here the slope is \bold -\frac{2}{5}

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )

\sf y - 1 = \bold -\frac{2}{5} (x --10)

\sf y = \bold -\frac{2}{5} x -4 + 1

\sf y = \bold -\frac{2}{5} x -3

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.

3 0
2 years ago
Read 2 more answers
Help!! I’ll give points and brainliest
Evgen [1.6K]

I don't know this. Sorry. Good luck

5 0
2 years ago
Juan made a design with polygons. which polygon in juan's design is pentagon
larisa86 [58]
The pentagon is the one with 5 sides. Good Luck!

6 0
3 years ago
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Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript
PIT_PIT [208]

Answer:

  f(x)=4\sqrt[3]{16}^{2x}

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

  4\sqrt[3]{4}\approx 6.3496

The functions you're looking at seem to be ...

  f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x

The third choice seems to be the one you're looking for.

9 0
3 years ago
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A rectangle initially has dimensions 6 cm by 7 cm. All sides begin increasing in length at a rate of 1 cm/s. At what rate is the
Morgarella [4.7K]

Answer:

  49 cm²/s

Step-by-step explanation:

The problem statement tells you what to do.

Write an equation relating A, b, h:

  A = bh . . . . . . the equation for the area of a rectangle

Differentiate with respect to t:

  dA/dt = (db/dt)h + b(dh/dt) . . . . . . . product rule

To find the rate of change after 18 seconds, you need to know the dimensions b and h after 18 seconds. Since each dimension was increasing at the rate of 1 cm/s, it is 18 cm more than it was at the beginning:

At 18 seconds,

  b = 6 cm + 18 cm = 24 cm;

  h = 7 cm + 18 cm = 25 cm.

Of course, db/dt = dh/dt = 1 cm/s. Then the rate of change of area is ...

  dA/dt = (1 cm/s)(25 cm) + (24 cm)(1 cm/s)

  dA/dt = 49 cm²/s

_____

You could write a formula for the area as a function of time and differentiate that:

  A = (6 +t)(7 +t) = 42 + 13t + t²

Then the derivative is ...

  dA/dt = 13 +2t

and when t=18, this is ...

  dA/dt = 13 + 2(18) = 49 . . . . cm²/s

7 0
3 years ago
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