8

This is actually fairly simple. If you take the x-1 and set it equal to 0 you get 1. And if you plug that value into the x you get 8, which is the remainder. This is called the remainder value theorem.

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2 years ago

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Given F(x)=1/x-4, g(x)=1/6-x. Find f+g(x).

Yakvenalex [24]

$\boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Explanation:</h2>

We are given two functions:

$f(x)=\frac{1}{4}x-4 \\ \\ g(x)=\frac{1}{6}-x$

So, we have to find $f(x)+g(x)$ which is the sum of these two functions:

$f(x)+g(x)=\frac{1}{x}-4+\frac{1}{6}-x \\ \\ \\ Let's \ call \ h(x)=f(x)+g(x) \\ \\ Simplifying: \\ \\ h(x)=\left(\frac{1}{x}-x)+(-4+\frac{1}{6}) \\ \\ \\ \\$

$Finally: \\ \\ \boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

3 0

2 years ago