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ddd [48]
3 years ago
5

I need help with number 11 and number 12

Mathematics
2 answers:
ladessa [460]3 years ago
6 0

Answer:

6 and 3

Step-by-step explanation:

Using the rules of logarithms

logx^{n} ⇔ n log x

log_{b} x = n ⇒ x = b^{n}

log_{a} a = 1

(11)

let 2 log_{2}8 = n , then

log_{2} 8² = n

log_{2} 64 = n

log_{2} 2^{6} = n

2^{6} = 2^{n}

Since bases on both sides are equal, equate the exponents, that is

n = 6

(12)

log_{a} a³

= 3 log_{a} a

= 3 × 1

= 3

arlik [135]3 years ago
4 0

Answer:

11) 6

12) 3

Step-by-step explanation:

2 log 2 8

so 2(log2 8)

Base 2 so 2^x=8 so 3.

2*3 is 6.

log a a cubed

base a so a^ x = a^3

x=3

so 3.

Hope this helps ;D

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3 years ago
What is the equation of the line that passes through the point (-4,-6) and has an
olga_2 [115]
X= -4

Explanation:
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5 0
3 years ago
How many solutions does the following equation have<br> 3(f - 5) = 6f - 12 + 3f
Crazy boy [7]

Answer: Two answers: f=-3

f=3

Step-by-step explanation:

3(f-5)=6f-12+3f

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Answer2

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5 0
3 years ago
One pound of grout is enough to grout a tiled area that is 110 sq. Ft. Alyssa's kitchen counter is made up of two rectangular se
Ratling [72]

Answer:

(10.3(2.5)+3.1(2))\div 110

Step-by-step explanation:

A_1 = Area of 1st rectangle = (10.3\times 2.5)\ \text{ft}^2

A_2 = Area of 2nd rectangle = (3.1\times 2)\ \text{ft}^2

1\ \text{pound of grout}=110\ \text{ft}^2

\Rightarrow 1\ \text{ft}^2=\dfrac{1}{110}\ \text{pound of grout}

The number of pounds required for the counter top is

\text{Total area}\times \text{The amount of grout used in 1 ft}^2

=A_1+A_2\times \dfrac{1}{110}=(10.3(2.5)+3.1(2))\times \dfrac{1}{110}\\ =(10.3(2.5)+3.1(2))\div 110

The required expression is (10.3(2.5)+3.1(2))\div 110.

6 0
3 years ago
Read 2 more answers
Multiplying Monomials and Binomials multiply 15w(w+15)
sleet_krkn [62]
The answer is 15w^2 + 225w


Key:

^ - Means that it is an exponent, in case you didn't know :)
3 0
3 years ago
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