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m_a_m_a [10]
2 years ago
5

Can someone help pls

Mathematics
2 answers:
Leya [2.2K]2 years ago
4 0

Answer:

Slope = 4/3

Step-by-step explanation:

Formula for slope-intercept form: y=mx + b

Given: 3y - 4x = -6

Add -4x to the right hand side to isolate out 3y (y).

It should look like this: 3y = 4x -6

Now divide both sides by 3.

You should get: y = 4/3x -2

Since it's asking for slope, your slope is 4/3.

skelet666 [1.2K]2 years ago
3 0
Slope=4/3 this is the correct answer
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What is 7.58e8 Expressed the standard notation
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2 years ago
PLEASE ANSWER 14 points!!!!
katen-ka-za [31]

Answer:

5

Step-by-step explanation:

sqrt[(-8+3)² + (-6+6)²] = 5

4 0
2 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
2 years ago
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