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2 years ago

Y = -2, 3y-4 evaluate it please

Mathematics

1 answer:

Luba_88 [7]2 years ago

7 0

the answer is -10 you just multiply 3 times -2 and then subract 4

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Describe how the graph of each function differs from the graph of f(x)=|x|. Then determine the domain and range.

Brilliant_brown [7]

A. We can compress the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $0$ Since $0$ , the graph of the function $g(x)= 0.6|x|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction.

B. We can stretch the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $C>1.$ Since $4>1,$ , the graph of the function $g(x)= 4|x-3|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction and translation 3 units to the right.

C. We can flip the graph of the function $f(x)=|x|$ upside down by multiplying the whole function by −1, then translate 1 unit to the left and 5 units up. Then we will get the function $g(x)=-|x+1|+5.$

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2 years ago

The diagram represents the shape and dimensions of Kayla's garden. A special fertilizer is used for the vegetable garden. Each b

Serjik [45]

Answer:

B. 18 bags

Step-by-step explanation:

First you need to determine the area of the vegetable garden. The vegetable garden is a rectangle with the following dimensions:

L = 24 ft

W = 9 ft

The Formula for the area of a rectangle is:

$A = L\times W$

So let's solve it:

$A = L\timesW\\A = 24 ft\times9ft\\A= 216ft^{2}$

With that, we can figure out how many bags of fertilizer would be needed by dividing the area of the vegetable garden by how much one bag of fertilizer covers:

$\dfrac{214ft^2}{12ft^2/bag}=18\;bags$

3 0

2 years ago

Read 2 more answers

in the diagram, a building casts a 35-ft shadow and a flagpole casts a 10-ft shadow. if the flagpole is 22tall, how tall is the

8_murik_8 [283]

Let, the height of the building be x ft.

Given the building casts 35ft shadow.

The height of the flagpole given which is 22ft and casts a shadow of 10ft.

Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.

So we can write,

x/35 = 22/10

To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.

(x/35)× 35 = (22/10)×35

x = (22×35)/10

x = 770/10

x = 77

So, the height of the building is 77 ft which is the required answer here.

8 0

2 years ago

Bob works at a construction company. He has an equally likely chance to be assigned to work diffrent crews every day. He can be

Sergio [31]

The answer is 6 times

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3 years ago

Planet X is 1/2 of a light-year away from Earth. Planet Y is 3/10 of a light-year away from Earth. How much farther away is Plan

kakasveta [241]

Answer:

1/2= 5/10

5/10 - 3/10 = 2/10 or 1/5

so planet X is 1/5 of a light-year closer

Step-by-step explanation:

8 0

2 years ago

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Y = -2, 3y-4 evaluate it please​

Y = -2, 3y-4 evaluate it please