Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
======================================================
Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Answer:
The average rate of change is -3.
Step-by-step explanation:
Given : Function 
over the interval 2 ≤ x ≤ 4.
To find : What is the average rate of change ?
Solution :
Function over [2,4]
The rate of change is the slope of the line,
So, 
Substitute,
Therefore, The average rate of change is -3.
Multiply 17x5=85,85+5=90 so aswer is 90
PART 1:55-21=35
35/60=<span>.58333
360</span>×<span>.58333 =210 DEGREES
</span><span>210*pi/180 = 3.665 RADIANS
PART 2: </span><span>(pi) x 2r x .58333
</span><span>3.14 x 12 x .58333 = 21.98 in
PART 3: </span><span>5π inches = 5 x 3.14 = 15.708 inches / 6 in radius = 2.618 radians
PART 4: </span><span>2.618 radians * 180/pi = 150° </span>
<span> x coordinate = 6(cos 150°) = -5.196 </span>
<span> y coordinate = 6(sin 150°) = 3 </span>
<span> the coordinates would be (-5.196, 2)</span>
Answer:
C. You have to multiply both powers to simplify.
