Answer:
A will get 9, B will get 12 and C will get15 chocolates
:-)
let's firstly, convert the mixed fractions to improper, and then do equation.
![\bf \stackrel{mixed}{3\frac{4}{5}}\implies \cfrac{3\cdot 5+4}{5}\implies \stackrel{improper}{\cfrac{19}{5}} ~\hfill \stackrel{mixed}{2\frac{5}{7}}\implies \cfrac{2\cdot 7+5}{7}\implies \stackrel{improper}{\cfrac{19}{7}} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B4%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%205%2B4%7D%7B5%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B5%7D%7D%0A~%5Chfill%0A%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B5%7D%7B7%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%207%2B5%7D%7B7%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B7%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D)
20x + 15k is the answer we just have to remove the bracket and add the terms
hope it helps
The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range. So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.
|18.62-18.25|>.36
.37>.36
18.62 is not in range.
Answer:
The win percentage decreased by 10%
Step-by-step explanation:
First you need to fin the total games played right before Melissa got Injured
41+23=64
Then you need to find the win percentage by making a fraction of wins over total games
wins/total games = 41/64 = 64%
Then you need to find the number of games played after Melissa got injured
54-41 = 13 wins
34-23 = 11 losses
13+11 = 24 total games played without Melissa
You find that win percentage similarly to the first time
wins/total games = 13/24 = 54%
Then you find the difference in the percentages and there you have it!!
64% - 54% = 10%
It decreased as well therefore the answer is...
It decreased by 10%
