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Mashutka [201]
3 years ago
15

X is a normally Distributed random variable with a standard deviation of 4.00. Find the mean of X when 64.8% of the area lies to

the left of 8.52.
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

7

Step-by-step explanation:

σ = 4 ; μ =?

8.52 to the left of X

.

P(X < 8.52) = 64.8%

P(X < 8.52) = 0.648

Using the Z relation :

(x - μ) / σ

P(Z < (8.52 - μ) / 4)) = 0.648

The Z value of 0.648 of the lower tail is equal to 0.38 (Z probability calculator)

Z = 8.52 - μ / 4

0.38 = 8.52 - μ / 4

0.38 * 4 = 8.52 - μ

1.52 = 8.52 - μ

μ = 8.52 - 1.52

μ = 7

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The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how
nikklg [1K]

I hate rounding.

Let's call the diagonal x.  It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})

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x = \frac 1 2(9 \pm \sqrt{329})

That's the exact answer.  Did I mention I hate rounding?  That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent.  By the Pythagorean Theorem the diagonal satisfies

x^2 = (x-4)^2 + (x-5)^2

which works out to

x=9 \pm 2\sqrt{10}

That's not consistent with the first answer; this problem really has no solution.  Tell your teacher to get better material.

5 0
3 years ago
A rectangular painting by Leonardo da Vinci measured 62cm along its diagonal. If the painting has a height of 42 cm how wide is
IRINA_888 [86]

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

{w}^{2}  +  {42}^{2}  = {62}^{2}

{w}^{2} = {62}^{2} -  {42}^{2}

{w}^{2}  = 2080

{w} =  \sqrt{2080}

w = 4 \sqrt{130}

The width of the painting is 45.6cm to the nearest tenth.

4 0
3 years ago
Does anyone know the answer??
dangina [55]

Answer:

Step-by-step explanation:

The answer A on 2021

4 0
2 years ago
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