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soldier1979 [14.2K]
3 years ago
5

12 = 1.5x Solve each equation algebraically

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0

Answer:

35

Step-by-step explanation:

I am assuming you want me to answer the equation provided in the picture, therefore I will provide you with the answer.

So we have \frac{3}{5} x = 21

When it comes to equations with a variable, our goal is to isolate the variable, so let's start.

\frac{3}{5} x = 21

1. Combine multiplied terms into a single fraction :

\frac{3x}{5} = 21

2. Multiply both sides by the denominator :

5 * 3/5 = 3

5 * 21 = 105

3x = 105

3. Divide both sides by 3 :

\frac{3x}{3} = \frac{105}{3 }

x = 35

Arada [10]3 years ago
5 0

Answer:

x=8

Step-by-step explanation:

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The perimeter of a rectangular field is 60ft and its width is 20ft find the area of this field
Gennadij [26K]

Perimeter of rectangle = 2( length +width)

given: Perimeter=60 ft and width=20 ft

plugging these values in the formula,

60=2(20+ length)

dividing both sides by 2

30=20+length

length =30-20=10

length is 10 feet

width is 20 feet

Area of rectangle is given by:

Area = l*w

Area = 10 *20 = 200 square feet

Answer : Area of rectangle is 200 square feet.

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4 years ago
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▹ Answer

<em>-1 - 1/2x</em>

▹ Step-by-Step Explanation

3x ÷ x - 4 + x - 3 ÷ 2x

Divide and Rewrite:

3 * 1 - 4 + x - 3 ÷ 2 * x

Calculate:

3 - 4 + x - 3/2x

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3 years ago
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Damon's father started a college fund on Damon's 8th birthday. He deposited $7500 into a CD (certificate of credit) that yields
algol13

Answer:

7672.50

Step-by-step explanation:

7500×0.23%=17.25

17.25×10=172.50

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3 years ago
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Answer:

Null Hypothesis, H_0 : \mu = 1,100 square feet

Alternate Hypothesis, H_A : \mu < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

<u><em>Let </em></u>\mu<u><em> = mean area of several apartments.</em></u>

So, Null Hypothesis, H_0 : \mu = 1,100 square feet

Alternate Hypothesis, H_A : \mu < 1,100 square feet

Here, <u>null hypothesis states that</u> the mean area of apartments are same as advertised.

On the other hand, <u>alternate hypothesis states that</u> the mean area of apartments are smaller than advertised.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

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157 square yards....
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