For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x) [No Relation]
(-x)^n = x^n for n -> even
(-x)^n = -x^n for n -> odd
In your example:
f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1 ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x) [between the bracket was the original fn]
f(x) = - f(-x)
so the function is odd also called symmetric about the origin
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9514 1404 393
Answer:
1/4
Step-by-step explanation:
The slope can be found using the slope formula with the two left-most marked points:
m = (y2 -y1)/(x2 -x1)
m = (6 -5)/(0 -(-4)) = 1/4
The slope of the line is 1/4.
Answer:
The ball reached its maximum height of (
) in (
).
Step-by-step explanation:
This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.
The first step in completing the square is to group the quadratic and linear term:

Now factor out the coefficient of the quadratic term:

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

Now take the balancing term out of the parenthesis:

Simplify:

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

Solutions
First Lets solve for this equation
Therefore this given equation is a <span>dependent system.
</span>
<span>Solve for </span>
There are too many solutions to these equations.