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2 years ago

Question 3 (2 points

1 answer:

7 0

(n-2)multiple 180 degrees the formula for finding the sum of all angles in a polygon regular here n represents the number of sides of the polygon.

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A triangle has 2 sides that are 9 inches and the bottom is 6 inches what is the height?

Elanso [62]

The height of the isosceles triangle is 8.49 inches.

<h3>How to find the height of the triangle?</h3>

Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.

So this is an isosceles triangle.

We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.

By Pythagorean's theorem, we can write:

(9in)^2 = (3 in)^2 + h^2

Where h is the height that we are trying to find.

Solving that for h we get:

h = √( (9 in)^2 - (3in)^2) = 8.49 inches.

We conclude that the height of the isosceles triangle is 8.49 inches.

If you want to learn more about triangles:

brainly.com/question/2217700

#SPJ1

8 0

1 year ago

118 {121÷(11×11)-(-4)-(3-7)}

Rama09 [41]

Question:

To Simplify:

118 {121÷(11×11)-(-4)-(3-7)}

Solution:

↠118 {121÷121+4-(-4)}

↠118 {1+4+4}

↠118 {5+4}

↠118{9}

↠118×9

↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

About BODMAS:

B→ Bracket

O→ Of

D→ Division

M→ Multiplication

A→ Addition

S→ Subtraction

5 0

2 years ago

Read 2 more answers

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

3 years ago

What is the answer to 7(1 + 4k)

Sophie [7]

How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k

so the answer is: 7+28k

i hope i have been helpful :)

8 0

2 years ago

Read 2 more answers

What are the zeros of the function f(x)= 2x^2-4x-6

jolli1 [7]

The root are x=3 and x=-1

youre welcome :)

5 0

3 years ago