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ss7ja [257]
2 years ago
14

Frank invests $1,000 in simple interest investment account that pays 8% a year. After a number of years, he withdraws his balanc

e of $2,200. Using the formula I = P r t, how many years was his money invested? Work backwards-but find the Interest first!
Mathematics
1 answer:
elena-s [515]2 years ago
6 0

Answer:

15 years

Step-by-step explanation:

Given data

P=$1,000

R=8%

A= $2200

I= A-P

I=2200-1000

I=$1200

Applying the formula

I=PRT/100

1200=1000*8*T/100

cross multiply

1200*100= 8000T

120000= 8000T

divide both sides by 8000

T=120000/8000

T=15  years

Hence the time is 15 years

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G(x)=x3 -2x2+5x-8g(-5)
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Answer:

g(x)=x3-2x2+5x+40g

Step-by-step explanation:

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Tamara invested $15,000 in an account that pays 4% annual simple interest. Tamara will not make any additional deposits or withd
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3 years ago
Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,
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Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by a_0=0 a_n=a_{n-1}+3n-1

To find : Write out the first 5 terms of this sequence ?

Solution :

a_n=a_{n-1}+3n-1 and a_0=0

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

a_1=a_{1-1}+3(1)-1

a_1=a_{0}+3-1

a_1=0+2

a_1=2

For n=2,

a_2=a_{2-1}+3(2)-1

a_2=a_{1}+6-1

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a_2=7

For n=3,

a_3=a_{3-1}+3(3)-1

a_3=a_{2}+9-1

a_3=7+8

a_3=15

For n=4,

a_4=a_{4-1}+3(4)-1

a_4=a_{3}+12-1

a_4=15+11

a_4=26

For n=5,

a_5=a_{5-1}+3(5)-1

a_5=a_{4}+15-1

a_5=26+14

a_5=40

The first 5 terms of the sequence is 2,7,15,26,40.

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