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Svetach [21]
3 years ago
10

Name the property shown by each statement.

Mathematics
2 answers:
Lelechka [254]3 years ago
4 0
The answer is a i believe
Black_prince [1.1K]3 years ago
3 0

Answer:

Commutative property multiplication (A)

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What is the value of x in the equation 1,331x3 − 216 = 0?
algol [13]
In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.
Hope yhis helps
4 0
3 years ago
Read 2 more answers
Please help me if you know how to do this!
lukranit [14]

Question 21

Let's complete the square

y = 3x^2 + 6x + 5

y-5 = 3x^2 + 6x

y - 5 = 3(x^2 + 2x)

y - 5 = 3(x^2 + 2x + 1 - 1)

y - 5 = 3(x^2+2x+1) - 3

y - 5 = 3(x+1)^2 - 3

y = 3(x+1)^2 - 3 + 5

y = 3(x+1)^2 + 2

Answer: Choice D

============================================

Question 22

Through trial and error you should find that choice D is the answer

Basically you plug in each of the given answer choices and see which results in a true statement.

For instance, with choice A we have

y < -4(x+1)^2 - 3

-7 < -4(0+1)^2 - 3

-7 < -7

which is false, so we eliminate choice A

Choice D is the answer because

y < -4(x+1)^2 - 3

-9 < -4(-2+1)^2 - 3

-9 < -7

which is true since -9 is to the left of -7 on the number line.

============================================

Question 25

Answer: Choice B

Explanation:

The quantity (x-4)^2 is always positive regardless of what you pick for x. This is because we are squaring the (x-4). Squaring a negative leads to a positive. Eg: (-4)^2 = 16

Adding on a positive to (x-4)^2 makes the result even more positive. Therefore (x-4)^2 + 1 > 0 is true for any real number x.

Visually this means all solutions of y > (x-4)^2 + 1 reside in quadrants 1 and 2, which are above the x axis.

5 0
3 years ago
Match the numbers to the letters for equivelents
ruslelena [56]
Use desmos to find th as t answer
5 0
3 years ago
Solve the following equation for x. x = -2 x = 2 x = -17 x = -7 (x - 5)/2 = -6
nordsb [41]

Step-by-step explanation:

x= -2,

(x - 5) / 2= -6

( (-2) - 5) / 2= -6

(-7) / 2 = -6

-3.5 = - 6

right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.

x=2,

(x - 5) / 2= -6

(2 - 5) / 2= -6

(-3) / 2= -6

-1.5 = - 6

right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.

x= -17

(x - 5) / 2= -6

( ( -17) - 5) / 2= -6

(- 22) / 2= -6

-11 = -6

right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.

x= -7,

(x - 5) / 2= -6

( ( -7) -5) / 2= -6

(-12) / 2= -6

-6= -6

right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.

8 0
3 years ago
What is the equation of the line that passes through the point (−3,−11) and is parallel to the line with the equation y=2x−4
tester [92]

parallel means same slope.  m = 2

y - y₁ = m(x - x₁)

y - (-11)= 2(x - (-3))

y + 11 = 2(x + 3)

y + 11 = 2x + 6

<u>   -11  </u>  <u>       -11  </u>

    y = 2x - 5

Answer: A

5 0
3 years ago
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