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sergeinik [125]
3 years ago
6

Y=10x Select the answer showing the ratio x:y

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

x:y/10

Step-by-step explanation:

y=10x

y/10=10x/10

y/10=x

x=y/10

x:y/10

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What is an equation of the line with slope 3 that goes through point (2/3, 4)
qwelly [4]
A. All the equations are in slope intercept form, so all that's needed to do is plug in 2/3 as the x value in each equation and if the result is 4, then you got the answer.
6 0
3 years ago
A ball is thrown from an initial height of 2 meters with an initial upward velocity of 15/ms . The ball's height h (in meters) a
Irina-Kira [14]
The height that a ball reaches at a certain time t is given by the equation,
           h = 2 - 15t + 5t²
We are asked to compute for the values of t that would allow the ball to reach a height of 7 meters. 

Substitute the 7 to the equation,
         7 = 2 - 15t + 5t²
Transposing,
               5t² - 15t - 7 + 2 = 0
Simplifying,
               5t² - 15t - 5 = 0
Divide the equation by 5,
               t² - 3t - 1 = 0

The values of t can be calculated through the quadratic formula,
             t = (-b +/- sqrt(b² - 4ac))/2a

Substituting, 
             t = (3 +/-sqrt (9 - 4(-1)) / 2(1)
              t = 3.3 or t = -0.30

Since, we cannot have t as a negative number hence, our final answer is:
      <em> t = 3.3 s</em>
4 0
3 years ago
Lanie's Room Is In The Shape Of A Parallelogram. The Floor Of Her Room Is Shown And Has An Area Of 108 Square Feet. Lanie Has A
Natasha2012 [34]

Answer:

The rug will fit on the floor of her room

Step-by-step explanation:

The floor's area is given as 108

Will the rug fit this area of 108 sq. ft.?? We have to find the area of the rug and if it is less than 108, then definitely it will fit.

The rug is in the shape of a rectangle. The area of a rectangle is length times width.

Given length 10 and width 6, the area is:

Area of Rectangle = 10 * 6 = 60

Area of Rug = 60

Is 60 less than 108?? Yes, definitely!

The rug will fit on the floor of her room

6 0
3 years ago
Question 13
Mrac [35]

Answer:

71.6 degrees

Step-by-step explanation:

Given the vectors

u= <8,4> v = <9.-9> (5 points)

u*v = (8, 4)*(9, -9)

u*v = 8(9)+(4)(-9)

u*v = 72 - 36

u*v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+9²

|v|  = √81+81

|v|  = √162

Using the formula

u*v = ||u||v| cos theta

36 = √80(√162)cos theta

36 = √12960 cos theta

cos theta = 36/√12960

cos theta = 36/113.8

cos theta = 0.3162

theta = arccos(0.3162)

theta = 71.56 degrees

Hence the angle between the given vectors to the nearest tenth of a

degree is 71.6 degrees

5 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
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