Answer:
The problem:
Find 
if 
,
![h(x)=\sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B3%7D)
, and
![f(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
.
Step-by-step explanation:
Replace 
in with since we are asked to find 
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:
![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
![\sqrt[3]{x+3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D)
which is the required result for 
.
Area = length x width
24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15
Length is 15-3 =12, width is 2
24 = 12 x 2
A rotation around the origin of 180° and an enlargement by a scale factor of 3
Answer:
y will be in every single quadrant
Step-by-step explanation:
So we have the equation 
first we will have to look at the equation. It says that y is less than or equal to 
since y is less than the only place the shaded area where y can be is under the line that is drawn be the equation. When the equation is graphed the y-intercept will be on positive 1 it since slope is rise over run it will look something like the file attached to this. so under the line you can see every single quadrant so that is why it would be that way
