Which of these 3 curves drawn matches the graph of y=2x^2+x

Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship

yan [13]

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

6 0

1 year ago

3/4 Tones = __ lb???? HELP ASAP Thank you

Shtirlitz [24]

The answer is 1500 pound because 1 ton = 2,000 pounds. 1/4 of a ton = 500 pounds. So 3/4 tons = 500*3 =1500 pounds.

6 0

3 years ago

Read 2 more answers

mr. ronaldo earns 54,800 annually. if his income tax rate is 9% then how much did he pay in income tax

Alik [6]

Answer:

Mr Ronaldo paid $4,932 in income tax

Step-by-step explanation:

In this question, we are asked to calculate the amount Mr Ronaldo pays in income tax

To calculate this, we need to calculate 9% of his annual earnings

His income tax = 9/100 * 54,800

Income tax = $4,932

3 0

3 years ago

At Yo-Yo Yogurt, the scale says that Sara has 8 ounces of vanilla yogurt in her cup. Her father’s yogurt weighs 11 ounces. How m

saveliy_v [14]

Answer: $1 \frac{3}{16}\ lb$

Step-by-step explanation:

You know that Sara has 8 ounces of vanilla yogurt in her cup and her father’s yogurt weighs 11 ounces. Then, the total ounces of frozen yogurt they buy altogether is:

$total_{(ounces)}=8\ oz+11\ oz\\\\total_{(ounces)}=19\ oz$

The next step is to make the conversion from ounces to pounds.

You need to remember that:

$1\ lb=16\ oz$

Therefore:

$total_{(pounds)}=(19\ oz)(\frac{1\ lb}{16\ oz})=\frac{19}{16}\ lb$

This result expressed as a mixed number, is:

$total_{(pounds)}=1\frac{3}{16}\ lb$

8 0

3 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$

Then, the margin of error is:

$MOE=z \cdot s_{pm-pw}=1.645\cdot 0.029=0.0477$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.212-0.0477=-0.260\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.212+0.0477=-0.165$

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

6 0

3 years ago