<u>Answer</u>
48
<u>Explanation</u>
The product of the secant and the extension of the chord is normally equivalent to square of the tangent.
From the diagram given,
The length of the secant = 2+6
= 8
Length of the extension of the chord = 6
length of the tangent = x
∴ x² = 8 × 6
= 48
Answer:
= 1+2n and 63
Step-by-step explanation:
the question belongs to arithmetic sequence and can be determined by the formula
= a1 + d (n-1)
Let " " represents the number of band members in the nth row
and 'd' represents the common difference.( as stated each row has 2 more band members than the row before it)
therefore, d=2
'a1' represents first row that has three members. So, a1 = 3
->Rule for nth term will be:
= 3 + 2(n-1)
= 3 + 2n -2
= 1+2n
-> In order to find total number of band members '
'
Let 
represent total number in n rows
We'll use the formula, i.e = n/1 (
+ )
where, n is the number of terms, is the first term and is the last term
So,
n=7
= 1 + 2(7)= 15
=> = 7/2 (3 + 15)
= 63
The total number of band members are 63
Answer:
0.41<3.40/x<0.50
Step-by-step explanation:
Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,
If the cost of one banana is P, then, the inequality will be
0.41 < P < 0.50
Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below
3.40/0.41 = 8.29
3.40/0.50 = 6.8
Therefore, the inequality that represents the range of possible pounds purchased is
6 < x < 9 this is the same as 0.41<3.40/x<0.50
Answer:
The answer is the third equation. A = 250*(1 +0.016)^(0.75)
Step-by-step explanation:
Since Javier deposited $250 into an account with annual interest rate, then as the years passes his account will grow in the manner shown below:
account(0) = 250
account(1) = account(0)*(1 + 1.6/100) = account(0)*(1 + 0.016) = account(0)*1.016
account(2) = account(1)*1.016 = account(0)*1.016*1.016 = account(0)*(1.016)²
account(3) = account(2)*1.016 = account(0)*(1.016)²*1.016 = account(0)*(1.016)³
account(n) = account(0)*(1.016)^n
Where n is the number of years, account(0) is the initial amount. In this case only 9 months have passed, so we need to convert this value to years, dividing it by 12, which is 9/12 = 0.75. The initial amount was 250, so the equation is:
A = 250*(1.016)^(0.75)
The answer is the third equation.
