Express as a trinomial.<br> (2x – 4)(3x

Victoria spent one-fourth of her birthday money on clothes. She received another $25 a week later. If she has a total of $70 now

tia_tia [17]

Answer:

she had $60 before she went for shopping

Step-by-step explanation:

PLZ MARK BRAINLIEST

Let x represent the amount of money that Victoria had before she went for shopping.

Victoria spent one-fourth or her birthday money on clothes. It means that the amount she spent on shopping is 1/4 × x = x/4. Amount that she was having left would be x - x/4 = 3x/4

She received another 25$ a week later. The amount that she is having at this point will be 3x/4 + 25

If she has a total of 70$ now, it means that

3x/4 + 25 = 70

Multiplying through by 4

3x + 100 = 280

3x ,= 280 - 100 = 180

x = 180/3 = 60

3 0

3 years ago

Cube and cube roots 27000<br>

boyakko [2]

Answer:

lcm for cuberoot

2*2*2*5*5*5*3*3*3

for cuberoot we will make pairs of common three numbers and write them one time

2*5*3

30

check 30*30*30=27000

cube

multiply 27000 three times with itself

19683000000000.0 is the answer

6 0

3 years ago

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Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

3 years ago

What is the value of the expression 8 cubed?

Ierofanga [76]

Answer:

512

Step-by-step explanation:

8*8*8

64*8

512

5 0

3 years ago

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Find the ratio of 18 and 30 reduced to simplest form...

saveliy_v [14]

First you'll take 18/2 which equals 9. Then 30/2 which equals 15. Then you can divide both 9 and 15 by 3. So 9/3 equals 3 and 15/3 equals 5. So the answer is 3:5.

4 0

3 years ago

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Express as a trinomial. (2x – 4)(3x – 3) ASAP