Ask question

Ask question

All categories

2 years ago

8

–1 =n + 5 PLSS!!!! HELP!! I DONT KNOW THIS ONE!

1 answer:

navik [9.2K]2 years ago

8 0

I guess the would help you

You might be interested in

(5xy)^5 fully simplify

AfilCa [17]

Answer:

Ok so i'm pretty sure its 3125x^5y^5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A new graph is formed from y = 5x by changing the slope to 9 and y-intercept to 8. Which statement about the new relationship is

shusha [124]

Answer:

The new graph has a steeper slope and a y-intercept of 8.

Step-by-step explanation:

From Analytical Geometry, we define a straight line by following first order polynomial (linear function):

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$b$ - y-Intercept.

$m$ - Slope.

And the slope represents the change in dependent variable ( $\Delta y$ ) divided by the change in independent variable ( $\Delta x$ ). That is:

$m = \frac{\Delta y}{\Delta x}$

If $m_{1} > 0$ and $m_{2} > m_{1}$ , then the new line is steeper with respect to the original line.

Let $y = 5\cdot x$ , its slope and y-intercept are 5 and 0, respectively. If slope is changed into 9 and y-intercept becomes 8, then the new graph has a steeper slope and a y-intercept of 8.

8 0

3 years ago

What is an expression that equals 24 but includes an exponet

quester [9]

3 x (2)³ is an expression that's equal to 24 .

6 0

3 years ago

Which graph represents the following system of inequalities.

Marta_Voda [28]

Answer: Graph C is correct

Step-by-step explanation:

The region below the dashed red line is y < 4/3x +2

The region below the solid purple line is y ≤ -1

The region below and left of the solid green line is y ≤ -3x

4 0

3 years ago

If y= 3x + 6, what is the minimum value of (x^3)(y)?

Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of $(x^3)(y)$

Let f(x) = $(x^3)(y)$

Substitute the value of y ;

$f(x)=(x^3)(3x+6)$

Distribute the terms;

$f(x)= 3x^4 + 6x^3$

The derivative value of f(x) with respect to x.

$\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)$

Using $\frac{d}{dx}(x^n) = nx^{n-1}$

we have;

$\frac{df}{dx} =(12x^3+18x^2)$

Set $\frac{df}{dx} = 0$

then;

$(12x^3+18x^2) =0$

$6x^2(2x + 3) = 0$

By zero product property;

$6x^2=0$ and 2x + 3 = 0

⇒ x=0 and x = $-\frac{3}{2} = -1.5$

then;

at x = 0

f(0) = 0

and

x = -1.5

$f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625$

Hence the minimum value of $(x^3)(y)$ is, -5.0625

3 0

3 years ago