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3 years ago

Solve -4 (h - 2) = 8

Mathematics

2 answers:

iragen [17]3 years ago

8 0

Answer:

h=0

Step-by-step explanation:

-4(h-2)=8

/4 /4

h-2=-2

h=0

Hey Btw I strongly reccomend you use photomath for your math classes.

NeX [460]3 years ago

7 0

Answer:

$\frac{ - 4(h - 2}{ - 4} = \frac{8}{ - 4} \\ h - 2 = - 2 \\ h - 2 + 2 = - 2 + 2 \\ h = 0$

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Your weather app says there's a 30% chance of rain that day. You know that if it rains, the probability that the bus runs late i

densk [106]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(rain) = p(R) = 30% = 0.3

P(being late Given that it rains) = P(late | rain) = p(L|R) = 0.4

P(being late Given no rain) = P(late | no rain) = 0.15

(a) What is the probability that it will rain and the bus will be late? = P(RAINnLate) = P(RnL)

P(RnL) = p(R) * p(L|R)

P(RnL) = 0.3 * 0.4

= 0.12

(b) What is the probability that the bus will be late?

P(L) = p(R) * p(L|R) + p(no rain) * p(late | no rain)

P(L) = (0.3 * 0.4) + (1 - 0.3)*(0.15)

P(L) = 0.12 + 0.105

P(L) = 0.225

Given that bus ran late, the probability that it was not raining = p(no rain | Late)

p(no rain | Late) = 1 - p(R | L)

Recall :

P(RnL) = p(L) * p(R|L)

0.12 = 0.225 * p(R|L)

p(R|L) = 0.12 / 0.225

p(R|L) = 0.5333

p(no rain | Late) = 1 - 0.533

= 0.46666

= 0.467

4 0

3 years ago

Help asap will give BRAINLIEST

dybincka [34]

The answer: d. < 1 and < 8

5 0

4 years ago

In 2007 Candace made 37 more field goals than she did in 2006, she had a total of 497 field goals for those years. How many fiel

d1i1m1o1n [39]

Heres what we know

X=2006 goals
y= 2007 goals
497 = X +Y which can be arranged to be y= 497 - x
y= 37 + x

soooo..
we make the y equations equal to each other

37 + x = 497 - x
2x = 460
x= 230

now plug that back into the original equation to check
y = 37 + (230)
y = 267

so in 2006 (remember x represents 2006 goals) she made 230 goals

6 0

3 years ago

An investor invested a total of $3 comma 500 in two mutual funds. One fund earned a 4% profit while the other earned a 2% pro

lesya [120]

Answer:

$2000 invested in first fund

$1500 invested in second fund

Step-by-step explanation:

An investor invested a total of $3,500 in two mutual funds.

Let x be the amount invested in first fund

first fund earned a 4% profit (4%= 0.04)

So interest is 0.04x for first fund

Let x be the amount invested in first fund

first fund earned a 4% profit (4%= 0.04)

So interest is 0.04x for first fund

Let y be the amount invested in second fund

second fund earned a =2% profit (2%= 0.02)

So interest is 0.02y for second fund

An investor invested a total of $3,500 in two mutual funds.

So x+y = 3500----> equation 1

y= 3500-x

the investor's total profit was $110

0.04x + 0.02y = 110----> equation 2

Plug in 3500 -x for y

0.04x + 0.02(3500-x) = 110

0.04x + 70 - 0.02x = 110

0.02x + 70 = 110

Subtract 70 onboth sides

0.02x = 40

Divide both sides by 0.02

x= 2000

y= 3500-x

so y= 3500 - 2000 = 1500

$2000 invested in first fund

$1500 invested in second fund

3 0

3 years ago

HELP QUICK OMG OMG

nexus9112 [7]

Answer:

put a pic up i haven't done this since 5th grade, so im kinda rusty

4 0

3 years ago