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Lostsunrise [7]

4 years ago

7

If a cross section of the paperweight is cut perpendicular to the base but does not pass through the top vertex, which shape des

cribes the cross section? rectangle triangle trapezoid hexagon

1 answer:

Montano1993 [528]4 years ago

4 0

Rectangle shape paper weight

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Solve for x Solve for x. 4x = 3/8<br> ASAP 30 POINTS

gregori [183]

X is equal to 0.09375. X is equal to 1/16.

5 0

3 years ago

olga nikolaevna [1]

If you use the real Pi , 3.140625 , from a real ratio 201 /64 , you would get 37.6875 inches . All ruler measurements like 1/2 , 1/4, 1/8 ,1/16 … is where the last decimal integer ends in 5 , just like the real Pi . If you use the present day Pi , your decimal integer circumference length keeps getting ever smaller , 10 , 100 , 1000 … in this case you would have a shrinking diameter . You are better off using the real Pi, that i have proven with Quora. Richard Eicholtz
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Related Questions (More Answers Below)

8 0

3 years ago

2/3x+5=1 what is the solution to the equation shown?

Fudgin [204]

Answer:

x = - 6

Step-by-step explanation:

Given

$\frac{2}{3}$ x + 5 = 1 ( subtract 5 from both sides )

$\frac{2}{3}$ x = - 4

Multiply both sides by 3 to clear the fraction

2x = - 12 ( divide both sides by 2 )

x = - 6

7 0

4 years ago

Read 2 more answers

Given the conditional statement below, what is the hypothesis? If you do your homework, then you will pass.

Zolol [24]

Answer:

The hypothesis is that by doing your homework for the class you will pass

Step-by-step explanation:

If you do your homework, you will pass the class

4 0

3 years ago

H(x) = 2^x<br>Solve the equation h^-1 (x) =0.5

Ludmilka [50]

Answer:

The answer is

<h2> $\sqrt{2} \: \: or \: \: 1.414$ </h2>

Step-by-step explanation:

<h3> $h(x) = {2}^{x}$ </h3>

To solve the equation we must first find h-¹(x)

To find h-¹(x) equate h(x) to y

That's

<h3> $y = {2}^{x}$ </h3>

<u>Next interchange the terms </u>

x becomes y and y becomes x

That's

<h3> ${2}^{y} = x$ </h3>

<u>Make y the subject</u>

Take logarithm to base 2 to both sides

That's

<h3> $log_{2}( {2} )^{y} = log_{2}x \\ y log_{2}2 = log_{2}(x)$ </h3>

But

<h3> $log_{2}(2) = 1$ </h3><h3> $y = log_{2}(x)$ </h3>

So we have

<h3> ${h}^{ - 1} (x) = log_{2}(x)$ </h3>

Now we can solve the equation

We have

<h3> $log_{2}(x) = 0.5$ </h3>

Convert the logarithm into exponential form using the fact that

<h3> $log_{a}(x) = b \: \: \cong \: \: x = {a}^{b}$ </h3>

So we have

<h3> $x = {2}^{0.5}$ </h3>

But

<h3> ${2}^{0.5} = \sqrt{2}$ </h3>

So we have the final answer as

<h3> $\sqrt{2} \: \: or \: \: 1.414$ </h3>

Hope this helps you

8 0

3 years ago