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Nastasia [14]
3 years ago
6

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, how man

y minutes would it take the slower pipe to fill the tank by itself? Your answer
Mathematics
1 answer:
Yanka [14]3 years ago
5 0

Answer: 144 minutes

Step-by-step explanation:

Based on the information that has been given in the question, the minutes that the slower pipe alone can use in filling the tank can be denoted by y minutes.

Therefore, the faster pipe will fill it in 1/3 × x = x/3 minutes.

Therefore,

1/x + 3/x = 1/36

4/x = 1/36

x = 36 × 4

x = 144

The number of minutes taken by the slower pipe will be 144 minutes.

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3 years ago
Find the derivative with respect to x of y = (3x + x^2)^5
RSB [31]
<h2>The required "option A) 5(3x + x^2)^{4} (3+2x)" is correct.</h2>

Step-by-step explanation:

We have,

y = (3x + x^2)^5          ..... (1)

To find, \dfrac{dy}{dx} = ?

Differentiating equation (1) w.r.t. 'x', we get

\dfrac{dy}{dx}= \dfrac{d[(3x + x^2)^5]}{dx}

⇒ \dfrac{dy}{dx}=5(3x + x^2)^{5-1} \dfrac{d(3x + x^2)}{dx}

[ ∵ y=x^{n} ⇒ \dfrac{dy}{dx}=nx^{n-1}]

⇒ \dfrac{dy}{dx}=5(3x + x^2)^{4} (3(1) + 2x^{2-1})

⇒ \dfrac{dy}{dx}=5(3x + x^2)^{4} (3+2x)

Thus, the required "option A) 5(3x + x^2)^{4} (3+2x)" is correct.

3 0
3 years ago
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zhannawk [14.2K]

Answer:

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5 0
3 years ago
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Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p
alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093

As a consecuence, he wont foul out with probability 0.9093.

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Answer:

The other answer is right. I got it wrong.

Step-by-step explanation:

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