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Nastasia [14]
2 years ago
6

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, how man

y minutes would it take the slower pipe to fill the tank by itself? Your answer
Mathematics
1 answer:
Yanka [14]2 years ago
5 0

Answer: 144 minutes

Step-by-step explanation:

Based on the information that has been given in the question, the minutes that the slower pipe alone can use in filling the tank can be denoted by y minutes.

Therefore, the faster pipe will fill it in 1/3 × x = x/3 minutes.

Therefore,

1/x + 3/x = 1/36

4/x = 1/36

x = 36 × 4

x = 144

The number of minutes taken by the slower pipe will be 144 minutes.

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Suppose that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}. Identify the pairs of sets in which one is a subset of th
OLEGan [10]

Answer:

Step-by-step explanation:

Given that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}.

We know that P is a subset of Q if all elements of P are also in Q

Using this let us compare pairwise

A and B

The elements of B are also in A

So B is a subset of A

Next A and C,

All elements of C are in A.  So C is a subset of A

B and C.  We find neither is a subset of other

B and D.  Here also 2 is not in D so not a subset

C and D

C is a subset of D

SO answer is

B and C are subsets of A and C is also a subset of D

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2 years ago
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Find angle N and arc NQ. See the image below.
malfutka [58]

Answer:

Angle N=32

Arc NQ=106

Step-by-step explanation:

Angle N is a inscribed angle of Arc MP so that means Angle N measures 32.

Angle NPQ is a inscribed angle of Arc NQ so that means Arc NQ is twice the measures of NPQ so

Arc NQ=106

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3 years ago
There are 100 tabs of acetaminophen in one bottle. There are 650mg in 2
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8 0
2 years ago
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5
miskamm [114]

Answer:  

z=-3.25

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=5.24 represent the mean production for the sample  

\sigma=0.32 represent the sample standard deviation for the sample  

n=16 sample size  

\mu_o =5.5 represent the value that we want to test  

\alph=0.05a represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean production is different from 5.5 tons, the system of hypothesis would be:  

Null hypothesis:\mu =5.5  

Alternative hypothesis:\mu \neq 5.5  

If we analyze the info given we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{5.24-5.5}{\frac{0.32}{\sqrt{16}}}=-3.25  

P-value

Since this is a two side test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the production its significant different compared to the desired percentage of SiO2 of 5.5 at 5% of signficance.  

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Step-by-step explanation:

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