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Stolb23 [73]
3 years ago
8

5. The number of atoms in 9.2 g of Na will be: A. 6.2 x 1023 atoms B. 2.408 x 1023 atoms C. 9.2 x1023 atoms D. 23 atoms E. 9.2 a

toms
Chemistry
1 answer:
cluponka [151]3 years ago
4 0

Answer:

The answer is "Option B"

Explanation:

Formula:

Na atoms= Na atoms moles \times  NA

               = \frac{mass}{Na \ Molar\ mass} \times 6.022 \times 10^{23}\\\\= \frac{9.2}{23} \times 6.022 \times 10^{23}\\\\=0.2875 \times 6.022 \times 10^{23}\\\\=2.4 \times  10^{23}\ atoms \\\\

                                     

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3.5 x 10^-4 is the answer ! :)
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3 years ago
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Which oxide(s) of manganese have a mass percent of the metal that is greater than 50%?MnO MnO2 Mn2O3All of these210
gtnhenbr [62]

Answer:

All of these oxides of manganese have a mass percent of metal greater than 50%

Explanation:

Step 1: Data given

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

<em><u>Step 2: Calculate mass % of Mn in MnO</u></em>

Molar mass of MnO = 54.94 + 16 = 70.94 g/mol

% Mn = (54.94/70.94)*100 % = 77.45 %

<u><em>Step 3: Calculate % of Mn in MnO2</em></u>

Molar mass of MnO2 = 54.94 + 2*16 = 86.94 g/mol

% Mn = (54.94/86.94) * 100% = 63.19 %

<u><em>Step 4: Calculate % of Mn in Mn2O3</em></u>

Molar mass of Mn2O3 = 2*54.94 + 3*16 = 157.88 g/mol

% Mn = ((2*54.94)/157.88)*100 % = 69.6 %

All of these oxides of manganese have a mass percent of metal  greater than 50%

5 0
3 years ago
N2(g) + 3H2(g) -&gt; 2NH 3(g)
Nutka1998 [239]

Answer:

None of the options are correct. The correct answer is:

56.67g

Explanation:

N2 + 3H2 —> 2NH3

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the equation,

6g of H2 produced 34g of NH3.

Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3

Therefore, 56.67g of NH3 are produced

5 0
4 years ago
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 7.00 moles of aluminum sulfate, al2(so4)3. express the nu
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We are given with 7 moles of a compound with a molecular formula of al2(so4)3 and is as asked here to determine the number of moles of Al, S and O. In a mole of aluminum sulfate, there are 2 moles of Al, 3 moles of S and 12 moles of O. Hence in total, there are 14 mol Al, 21 mol S, and 84 mol O. 
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I think it is A (10 %)
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